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Marina CMI [18]
3 years ago
9

Find the missing terms of the aritmetic sequence 5,a2,a3,a4,-11

Mathematics
1 answer:
Allushta [10]3 years ago
4 0
A2= 1
a3=-3
a4=-7
the common difference is -4

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Please help a girl out!! really confused
Flura [38]

Answer:14

Step-by-step explanation:To find the mean first add everything together and that will give you 84 then divide the total amount with the total amount of number  which is 6 and your answer is 14.

Step one:20+18+16+15+12+3=84  Step two:find the total amount of numbers which is 6.   Step three:divide 84÷6=14

5 0
2 years ago
Mrs. Steward needs to save (4.2 X 10^6) dollars for her children's college education. If she can save (1.4 X 10^2) each month, h
qwelly [4]

Answer: 30,000 months or 2,500 years

She'd better start saving more haha.

Step-by-step explanation:

Goal=4.2x10^6\\Savings/month=1.4x10^2

\frac{4.2x10^6}{1.4x10^2} =(\frac{4.2}{1.4})x10^(^6^-^2^)=(3)x10^4=3x10^4 =30000 months=\frac{30000}{12}=2500years

3 0
3 years ago
(Will give brainliest to correct answer)
AVprozaik [17]

D. there is a perfect association between the variables


7 0
3 years ago
9. Find the dimensions of the<br>4 triangular faces of the pyramid.<br>(Height is 55.5 ft)<br>​
Minchanka [31]

Answer:

Q=\frac{\pi}{2}*55.5ft=87.18ft\\P=87.18ft*\sqrt{\frac{1}{2}+\frac{16}{\pi ^{2}}}=87.18*0.9515=82.95ft\\

Step-by-step explanation:

We have a 4-sided triangular pyramid , where

Q=\frac{\pi}{2}*H\\P=Q*\sqrt{\frac{1}{2}+\frac{4}{\pi ^{2}}}\\Q=\frac{\pi}{2}*55.5ft=87.18ft\\P=87.18ft*\sqrt{\frac{1}{2}+\frac{16}{\pi ^{2}}}=87.18*0.9515=82.95ft\\

3 0
3 years ago
The plane x+y+2z=8 intersects the paraboloid z=x2+y2 in an ellipse. Find the points on this ellipse that are nearest to and fart
DiKsa [7]

Answer:

The minimum distance of   √((195-19√33)/8)  occurs at  ((-1+√33)/4; (-1+√33)/4; (17-√33)/4)  and the maximum distance of  √((195+19√33)/8)  occurs at (-(1+√33)/4; - (1+√33)/4; (17+√33)/4)

Step-by-step explanation:

Here, the two constraints are

g (x, y, z) = x + y + 2z − 8  

and  

h (x, y, z) = x ² + y² − z.

Any critical  point that we find during the Lagrange multiplier process will satisfy both of these constraints, so we  actually don’t need to find an explicit equation for the ellipse that is their intersection.

Suppose that (x, y, z) is any point that satisfies both of the constraints (and hence is on the ellipse.)

Then the distance from (x, y, z) to the origin is given by

√((x − 0)² + (y − 0)² + (z − 0)² ).

This expression (and its partial derivatives) would be cumbersome to work with, so we will find the the extrema  of the square of the distance. Thus, our objective function is

f(x, y, z) = x ² + y ² + z ²

and

∇f = (2x, 2y, 2z )

λ∇g = (λ, λ, 2λ)

µ∇h = (2µx, 2µy, −µ)

Thus the system we need to solve for (x, y, z) is

                           2x = λ + 2µx                         (1)

                           2y = λ + 2µy                       (2)

                           2z = 2λ − µ                          (3)

                           x + y + 2z = 8                      (4)

                           x ² + y ² − z = 0                     (5)

Subtracting (2) from (1) and factoring gives

                     2 (x − y) = 2µ (x − y)

so µ = 1  whenever x ≠ y. Substituting µ = 1 into (1) gives us λ = 0 and substituting µ = 1 and λ = 0  into (3) gives us  2z = −1  and thus z = − 1 /2 . Subtituting z = − 1 /2  into (4) and (5) gives us

                            x + y − 9 = 0

                         x ² + y ² +  1 /2  = 0

however, x ² + y ² +  1 /2  = 0  has no solution. Thus we must have x = y.

Since we now know x = y, (4) and (5) become

2x + 2z = 8

2x  ² − z = 0

so

z = 4 − x

z = 2x²

Combining these together gives us  2x²  = 4 − x , so

2x²  + x − 4 = 0 which has solutions

x =  (-1+√33)/4

and

x = -(1+√33)/4.

Further substitution yeilds the critical points  

((-1+√33)/4; (-1+√33)/4; (17-√33)/4)   and

(-(1+√33)/4; - (1+√33)/4; (17+√33)/4).

Substituting these into our  objective function gives us

f((-1+√33)/4; (-1+√33)/4; (17-√33)/4) = (195-19√33)/8

f(-(1+√33)/4; - (1+√33)/4; (17+√33)/4) = (195+19√33)/8

Thus minimum distance of   √((195-19√33)/8)  occurs at  ((-1+√33)/4; (-1+√33)/4; (17-√33)/4)  and the maximum distance of  √((195+19√33)/8)  occurs at (-(1+√33)/4; - (1+√33)/4; (17+√33)/4)

4 0
3 years ago
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