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4 years ago

Write the following decimal as a fraction or mixed

Mathematics

1 answer:

artcher [175]4 years ago

8 0

Answer:

$9 \frac{8}{1000}$

Step-by-step explanation:

9.008 * 1000 = 9008

9008 ÷1000 = 9 $9\frac{8}{1000}$

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Need help on precalculus

murzikaleks [220]

Answer:

arc = 15π

Step-by-step explanation:

The arc is calculated as

arc = circumference of circle × fraction of circle

= 2πr × $\frac{225}{360}$ ( r is the radius )

given diameter = 24 then r = 24 ÷ 2 = 12

arc = 2π × 12 × $\frac{5}{8}$

= 24π × $\frac{5}{8}$

= 3π × 5

= 15π

7 0

3 years ago

A gallon of gas has dropped to 2.85 if yesterday was 2.90 what is the percentage of decrease

vodomira [7]

Answer: 5%

Step-by-step explanation:

if it was 2.90 yesterday and 2.85 today there is a 5 cent decrease. to find the percent you convert .05 to a percent which is 5%

3 0

2 years ago

A local hamburger shop sold a combined total of 500 hamburgers and cheeseburgers on Wednesday. There were 50 more cheeseburgers

Komok [63]

500-250=250 so if there were 50 more cheeseburgers it would be 300 cheeseburgers so they would of have to sold 200 hamburgers on Wednesday to have sold 500 burgers in total do the answer is 200 hamburgers

4 0

3 years ago

Please someone help its a test

tino4ka555 [31]

Answer:

just choose E if you dont get it

Step-by-step explanation:

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cint%5Climits%5E5_1%20%7B%20%5Cfrac%7BlnR%7D%7B%20R%5E%7B2%7D%20%20%7D%20%5C%2C%20dR%20"

alex41 [277]

Integrate by parts, setting

$\begin{matrix}u=\ln R&&\mathrm dv=\dfrac{\mathrm dR}{R^2}\\\mathrm du=\dfrac{\mathrm dR}R&&v=-\dfrac1R\end{matrix}$

So the integral is

$\displaystyle\int_1^5\frac{\ln R}{R^2}\,\mathrm dR=-\dfrac{\ln R}R\bigg|_{R=1}^{R=5}+\int_1^5\frac{\mathrm dR}{R^2}$
$\displaystyle\int_1^5\frac{\ln R}{R^2}\,\mathrm dR=-\left(\frac{\ln5}5-\frac{\ln1}1)-\frac1R\bigg|_{R=1}^{R=5}$
$\displaystyle\int_1^5\frac{\ln R}{R^2}\,\mathrm dR=-\frac{\ln5}5-\left(\frac15-1\right)$
$\displaystyle\int_1^5\frac{\ln R}{R^2}\,\mathrm dR=\frac15(4-\ln5)$

5 0

4 years ago