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3 years ago

What is the fractional equivalent of the repeating decimal n = 0.1515... ?

Mathematics

2 answers:

alex41 [277]3 years ago

6 0

Answer:

Can someone help me with this too

Step-by-step explanation:

butalik [34]3 years ago

6 0

You have to have 10 digits at the least

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Please answer. Find the difference by subtracting the second polynomial from the first. for 10 points!!!!!!!!!!!!!

stellarik [79]

Answer:

$-3x^3+x$

Step-by-step explanation:

Let's first write the expression:

$-3x+x^3-2x^2-(4x^3-2x^2-4x)$

Now we can simplify. Be sure to remember to distribute the "-" to all the numbers in the parentheses. You can picture it like multiply "-1" to all the numbers in the parentheses to make it easier.

$-3x+x^3-2x^2-4x^3+2x^2+4x$

Now we combine like terms.

$x-3x^3$

Write the polynomials by decreasing exponents

$-3x^3+x$

8 0

2 years ago

-3|9x-7|=2 Find the answer for x

labwork [276]

<h2>Solving Equations with Absolute Expressions</h2><h3>Answer:</h3>

No Solutions

<h3>Step-by-step explanation:</h3>

Given:

$-3|9x -7| = 2$

Rewriting the given equation:

$-3|9x -7| = 2 \\ |9x -7| = -\frac{2}{3}$

We have to realize that the right side of the equation, $|9x -7|$ , will always be positive no matter what real values of $x$ (because we're taking the absolute value of the expression) and we are equating it to a negative constant number, $-\frac{2}{3}\\$ . Something that is always positive will never be negative so there's no value for $x$ that satisfies the solution.

$\rule{6.5cm}{0.5pt}$

You may not read the following passage that I have written.

$\rule{6.5cm}{0.5pt}$

Solving by positive of the expression:

$9x -7 = -\frac{2}{3} \\ 9x = -\frac{2}{3} +7 \\ 9x = -\frac{2}{3} +\frac{21}{3} \\ 9x = \frac{19}{3} \\ 9x \times \frac{1}{9} = \frac{19}{3} \times \frac{1}{9} \\ x = \frac{19}{27}$

Solving by the negative of the expression:

$-(9x -7)= -\frac{2}{3} \\ 9x -7 = \frac{2}{3} \\ 9x = \frac{2}{3} +7 \\ 9x = \frac{2}{3} +\frac{21}{3} \\ 9x = \frac{23}{3} \\ 9x \times \frac{1}{9} = \frac{23}{3} \times \frac{1}{9} \\ x = \frac{23}{27}$

Checking: $x = \frac{19}{27}\\$

$-3|9(\frac{19}{27}) -7| \stackrel{?}{=} 2 \\ -3|\frac{19}{3} -7| \stackrel{?}{=} 2 \\ -3|\frac{19}{3} -\frac{21}{3}| \stackrel{?}{=} 2 \\ -3|-\frac{2}{3}| \stackrel{?}{=} \\ -3(\frac{2}{3}) \stackrel{?}{=} 2 \\ -2 \stackrel{?}{=} 2 \\ -2 \neq 2$

$x = \frac{19}{27}\\$ is an extraneous solution.

Checking: $x = \frac{23}{27}\\$

$-3|9(\frac{23}{27}) -7| \stackrel{?}{=} 2 \\ -3|\frac{23}{3} -7| \stackrel{?}{=} 2 \\ -3|\frac{23}{3} -\frac{21}{3}| \stackrel{?}{=} 2 \\ -3|\frac{2}{3}| \stackrel{?}{=} \\ -3(\frac{2}{3}) \stackrel{?}{=} 2 \\ -2 \stackrel{?}{=} 2 \\ -2 \neq 2$

$x = \frac{23}{27}\\$ is an extraneous solution.

8 0

3 years ago

PLS HELP, WILL GIVE BRAINLIEST!

uranmaximum [27]

Answer:

Step-by-step explanation:

5 0

3 years ago

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Find the percent of change and state whether it was a percent of increase (I) or percent of decrease (D). from $289 to $762

hoa [83]

Answer:

163.67 ( I )

Step-by-step explanation:

6 0

3 years ago

It performs the following operations of the complex numbers would greatly appreciate friends...:)

Assoli18 [71]

(5i+4) + (4i-3)
5i+4i-3+4
9i - 1

(2+i) - (3+4i)
(2+i) + (-3 - 4i)
-1 -3i

Each part, real numbers and imaginary, are to be taken as separate pieces; add them with and subtract them by each other as you normally would. :)

3 0

3 years ago

Read 2 more answers