The sum its +2
2+2=4
4+2=6
6+2=8
8+2=10
And so on the numbers just keep sum for 2
So, you had done everything right so far (other than squaring the 2), but that was only half of the question.
to find the least common multiple, you need to first figure out what the prime factors have in common.

each have two twos. both have one 5, so we know our answer will look something like

now to figure out the other stuff... we have to represent the greatest amount of everything that is left, and we have 3s and 7s left over, so we need to figure out how many of each we need.
one has one 3 and one has two, so we need two threes. now our equation is

what's the only number we have to deal with? 7...
how many sevens does 60 have? 0, and 630 has 1, so we know we need one 7. our answer becomes
A 5 or a queen
52 cards per deck
each card repeats 4 times
a 5 or a queen
there are four 5's and four queens
4+4=8
probablity=desiredoutcomes/totalpossible
probablity=8/52
probablity=4/26
probablity=2/13
Answer:
From the origin, move 0.5 unit to the left along the x-axis and 1 unit vertically down, and place the point.
Step-by-step explanation:
hope this helps! :}
The least number of socks that rob can remove to guarantee he removed a pair of white socks without looking is15 socks