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Alex777 [14]
2 years ago
6

Which is the shorts side of the triangle?

Mathematics
1 answer:
cupoosta [38]2 years ago
3 0
Opposite of the right angle
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Write an equation you could use for this word problem. Do not need to solve.
blondinia [14]

Answer:

23 + x = 40

Step-by-step explanation:

Hi,

23 is the total amount your friend has. 23 + the total amount you have is equal to 40. Since we don't know how much you have, we can write x. Therefore, 23 + x = 40 would be correct.

Hope this helps :)

7 0
2 years ago
Read 2 more answers
Match The Term
GalinKa [24]

Answer:

jyyj    

Step-by-step explanation:

From the figure,

Radius matches with (F) that is a segment between the centre of a circle and a point on the circle.

Arc matches with (D) that is Circle A and the portion of the circle between points B and C is darkened.

Chord matches with (C) Circle A and a line segment connecting points B and C which are on the circle.

Secant matches with (E) that is Circle A and a line segment connecting points B and C which are on the circle.

Tangent matches with (A) that is a line intersects a circle in exactly one point.

Circumference matches (B) that is the distance around a circle.


4 0
3 years ago
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According to one cosmological theory, there were equal amounts of the two uranium isotopes 235U and 238U at the creation of the
FromTheMoon [43]

Answer:

6 billion years.

Step-by-step explanation:

According to the decay law, the amount of the radioactive substance that decays is proportional to each instant to the amount of substance present. Let P(t) be the amount of ^{235}U and Q(t) be the amount of ^{238}U after t years.

Then, we obtain two differential equations

                               \frac{dP}{dt} = -k_1P \quad \frac{dQ}{dt} = -k_2Q

where k_1 and k_2 are proportionality constants and the minus signs denotes decay.

Rearranging terms in the equations gives

                             \frac{dP}{P} = -k_1dt \quad \frac{dQ}{Q} = -k_2dt

Now, the variables are separated, P and Q appear only on the left, and t appears only on the right, so that we can integrate both sides.

                         \int \frac{dP}{P} = -k_1 \int dt \quad \int \frac{dQ}{Q} = -k_2\int dt

which yields

                      \ln |P| = -k_1t + c_1 \quad \ln |Q| = -k_2t + c_2,

where c_1 and c_2 are constants of integration.

By taking exponents, we obtain

                     e^{\ln |P|} = e^{-k_1t + c_1}  \quad e^{\ln |Q|} = e^{-k_12t + c_2}

Hence,

                            P  = C_1e^{-k_1t} \quad Q  = C_2e^{-k_2t},

where C_1 := \pm e^{c_1} and C_2 := \pm e^{c_2}.

Since the amounts of the uranium isotopes were the same initially, we obtain the initial condition

                                 P(0) = Q(0) = C

Substituting 0 for P in the general solution gives

                         C = P(0) = C_1 e^0 \implies C= C_1

Similarly, we obtain C = C_2 and

                                P  = Ce^{-k_1t} \quad Q  = Ce^{-k_2t}

The relation between the decay constant k and the half-life is given by

                                            \tau = \frac{\ln 2}{k}

We can use this fact to determine the numeric values of the decay constants k_1 and k_2. Thus,

                     4.51 \times 10^9 = \frac{\ln 2}{k_1} \implies k_1 = \frac{\ln 2}{4.51 \times 10^9}

and

                     7.10 \times 10^8 = \frac{\ln 2}{k_2} \implies k_2 = \frac{\ln 2}{7.10 \times 10^8}

Therefore,

                              P  = Ce^{-\frac{\ln 2}{4.51 \times 10^9}t} \quad Q  = Ce^{-k_2 = \frac{\ln 2}{7.10 \times 10^8}t}

We have that

                                          \frac{P(t)}{Q(t)} = 137.7

Hence,

                                   \frac{Ce^{-\frac{\ln 2}{4.51 \times 10^9}t} }{Ce^{-k_2 = \frac{\ln 2}{7.10 \times 10^8}t}} = 137.7

Solving for t yields t \approx 6 \times 10^9, which means that the age of the  universe is about 6 billion years.

5 0
3 years ago
Use the image below to answer the following question. What relationship do the ratios of sin x° and cos y° share?
Drupady [299]

Answer:

B

Step-by-step explanation:

y \times  {4 \div 14 \frac{10}{4 |25 \\ | } }^{2}

8 0
2 years ago
Use the expression 14X + 28Y + 21.. what is the greatest common factor
12345 [234]

Answer:

1

Step-by-step explanation:

None of these numbers are alike terms so the only number left is 1.

4 0
2 years ago
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