X+2y=2 …(1)
x-2y=-2…(2)
(1)-(2): (x+2y)-(x-2y)=2- (-2)
4y=4
y=1
subs y=1 into(1)
x+2(1) =2
x=0
so x =0 y=1
the answer is C
Answer: 33
Step-by-step explanation: Hope this helps! :)
Answer:
21
Step-by-step explanation:
21
Ok
first of all, for q(x)/p(x)
if the degree of q(x) is less than the degree of p(x),then the horizontal assemtote is 0
then simplify
any factors you factored out is now a hole, remember them
to find the vertical assemtotes of a function, set the SIMPLIFIED denomenator equal to 0 and solve
so
y=(x-5)/(x^2-1)
q(x)<p(x)
horizontal assemtote is y=0
no factors to simplify so no holes
set denomenator to 0 to find vertical assemtote
x^2-1=0
(x-1)(x+1)=0
x-1=0
x=1
x+1=0
x=-1
the horizontal assemtotes are x=1 and -1
I'm not sure I understand your question, but I believe the answer you're looking for is 57632.
