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Sloan [31]
3 years ago
9

What is the relationship between sin(90 degrees) and sin(-90 degrees)

Mathematics
1 answer:
Volgvan3 years ago
4 0

Answer:

sin(90\°)=-sin(-90\°)

Step-by-step explanation:

we know that

sin(90\°)=1

sin(-90\°)=-1

therefore

sin(90\°)=-sin(-90\°)

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Can you help find the quotient for 4/5 ÷ 10
pochemuha

Answer:

2/25

Step-by-step explanation:

5 0
4 years ago
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Line segment AB is dilated to create line segment A'B' using point Q as the center of dilation.
Rashid [163]

Answer:

2

Step-by-step explanation:

To find the scale of dilation, you have to compare the ratio of the after transform with before transform according to the center of dilation. In this case, the center of dilation is Q so you have to compare QA' : QA. We know that QA= 1.25 and AA' is 1.25. The distance of QA' will be:

QA'= QA + AA'= 1.25 + 1.25 = 2.5

The scale factor will be:

scale factor= QA' : QA.= 2.5 : 1.25

scale factor= 2

7 0
3 years ago
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A bag contains red, green, and yellow marbles. The probability of selecting a red marble is 35%. What is the probability of not
KonstantinChe [14]

Probablity of selecting a red marble= 35%

Probablity of not selecting a red marble= 100%-35%

=65%

Hope it helps you. Please mark brainliest.

6 0
3 years ago
A software company is releasing one of their products on a CD. The manufacturer charges a $5,500 setup fee and $1.00 per CD. App
olga_2 [115]
Setup Fee= $5,500Per CD Charge= $1.00Desired Cost Per CD= $3.50
x= number of CDs

Desired Cost Per CD= Cost per CD + Setup Fee
($3.50 * x)= ($1.00 * x) + $5,500multiply inside parentheses
$3.50x= $1.00x + $5,500subtract $1.00x from both sides
$2.50x= $5,500divide both sides by $2.50
x= 2,200 CDs

ANSWER: x= 2,200 CDs
Hope this helps!  :)



4 0
3 years ago
Read 2 more answers
Find the time required for an object to cool from 280°F to 220°F by evaluating the following where t is time in minutes. (Round
blsea [12.9K]

9514 1404 393

Answer:

  5.8496 min

Step-by-step explanation:

  \displaystyle t=\frac{10}{\ln{2}}\int_{220}^{280}{\frac{1}{T-100}}\,dT=\frac{10(\ln{(280-100)}-\ln{(220-100)})}{\ln{2}}=\frac{10\ln{(3/2)}}{\ln{2}}\\\\\boxed{t\approx5.8496\quad\text{min}}

__

Modern calculators can perform integration with high accuracy. This one gives the same result.

4 0
3 years ago
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