Answer b: the system of equations does not have a solution
Suppose the systems consits of two first grade equations with two varaibles. If the two equations are parallel you would obtaing a result like Vinnet.
This is an example:
x = y + 1
7x = 7y + 9
substitue to get:
7(y+1) = 7y +9
7y + 7 = 7y + 9
7=9
There is not mistake, the system has no solutions, because the two equations represent parallel lines, which do no intercept one to each other.
Answer:
9 units²
Step-by-step explanation:
We know that ΔCRQ and ΔBOP are right triangles because RQ and OP are perpendicular to CB.
ΔAOR must also be a right triangle because ∠AOR = ∠OBP and ∠ARO = ∠RCQ.
Because of the Angle-Angle-Angle theorem, we know that ΔAOR ≅ ΔBOP ≅ ΔCRQ.
AR/AO = OP/PB
3(1/2)(AR)(AO) = (1/2)(OP)(PB)
PB = 6, OP = 3
3 x 3 = 9 units²
Given:
The function is:
The table of values for the function g(x).
To find:
The equation that best compares the y-intercepts of f(x) and g(x).
Solution:
We have,
Putting 
, we get
So, the y-intercept of the function f(x) is -4.
From the given table of values, it is clear that the function f(x) passes through the point (0,-4). So, the y-intercept of the function g(x) is -4.
The y-intercept of f(x) is equal to the y-intercept of g(x).
Therefore, the correct option is A.
Answer:
<h2>The line that forms the shadow is 10.26 meters long, approximately.</h2>
Step-by-step explanation:
This problem is about a right triangle, becasue the truck and its shadow are perpendicular.
We are gonna call 
the distance of the shadow on the ground, as the image attached shows.
To find the answer, we need to use Pythagorean's Theorem, where the hypothenuse is 11.2 meters, and one leg is 4.5 meters.
Therefore, the line that forms the shadow is 10.26 meters long, approximately.
<u>Explanation</u><u> </u><u>:</u>
<h3 />
<u>By doing cross multiplication, we get-----</u>
=>p-6=3(p+7)
=>p-6=3p+21 =>p-3p=21+6
=>-2p=27
=>p=27/-2
=>p=-27/2
<h3><u>Verification:</u></h3>
<u>By,putting the value of p in the equation, we get----</u>
<u>(</u><u>LHS)</u>=(-27/2+7)/(-27/2-6)=1/3<u>(</u><u>RHS)</u>
=>(-27+14/2)/(-27-12/2)=1/3
=>(-13/2)/(-39/2)=1/3
=>-13/2×2/-39=1/3
=>1/3=1/3
<u>Hence,LHS=RHS verified.</u>
