To get the coordinates, we would use the midpoint formula (google it)
(X1-X2/2 , Y1+Y2/2)
(-3+0/2 , -1+1/2)
N: (-3/2,0)
9514 1404 393
Answer:
434 -49π ≈ 280.1 cm²
Step-by-step explanation:
The shaded area is the difference between the enclosing rectangle area and the circle area.
The rectangle is 14 cm high and 31 cm wide, so has an area of ...
A = WH
A = (31 cm)(14 cm) = 434 cm²
The circle area is given by ...
A = πr²
A = π(7 cm)² = 49π cm²
__
The shaded area is the difference of these, so is ...
shaded area = rectangle - circle
= (434 - 49π) cm² ≈ 280.1 cm²
The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
Learn more about computations on:
brainly.com/question/4658834
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Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
17+30=47
47=47
That is the associative property of addition
Answer:
F=0
Step-by-step explanation:
