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Radda [10]
3 years ago
8

What is the product?

Mathematics
2 answers:
xxMikexx [17]3 years ago
7 0

Answer:

{ \tt{(5r - 4)( {r}^{2} - 6r + 4) }} \\  = {  \tt{( {5r}^{3}  -  {30r}^{2}  + 20r - 4 {r}^{2} + 24r - 16) }} \\  = { \tt{ {5r}^{3} - 34 {r}^{2}  + 44r - 16 }}

Vladimir [108]3 years ago
7 0

Answer:

5r³ - 34r² + 44r - 16

Step-by-step explanation:

\small \sf \: (5r − 4)(r² − 6r + 4)

use the distributive property

5r × (r² − 6r + 4) - 4× (r² − 6r + 4)

5r³ - 30r² + 20r - 4r² + 24r - 16

combine like terms

5r³ - 30r² - 4r² + 20r + 24r - 16

5r³ - 34r² + 44r - 16

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A seal went 25 feet below sea level to catch a fish. A sea lion dove 10 feet less than three times as deep as the seal to catch
vfiekz [6]

Answer:

65 feet below sea level.

Step-by-step explanation:

With the information provided, we can create the following equation for the position of the sea lion (p)

p = 3x - 10

In this equation, x would be the final position of the seal when it caught the fish. Since we are told that the seal's position is 25 feet below sea level then we can plug in this value as x and solve for p...

p = (3 * 25) - 10

p = 75 - 10

p = 65

Finally, we can see that the sea lion's position is 65 feet below sea level.

7 0
3 years ago
Read 2 more answers
Find all solutions in the integers of the equation ||x−3|−5| = 10, where the bars indicate absolute value.
Helga [31]

Answer:

x = 18 or x = -12.

Step-by-step explanation:

||x-3|-5| = 10 only if |x-3|-5 = 10 or |x-3|-5 = -10, i.e., if |x-3|=15 or |x-3|=-5; but |x-3| cannot be equal to -5, because |x-3| should be a non-negative value. Therefore, the first equation is true only if |x-3|=15. |x-3| = 15 only if x-3 = 15 or x-3 = -15, i.e., x = 18 or x = -12.  We can verify this in the following way: ||18-3|-5|=||15|-5|=|10|=10 and ||-12-3|-5|=||-15|-5|=|15-5|=|10|=10. This verify that our solution is correct.

3 0
4 years ago
If f(x)=3x^2 and g(x)=4x^3+1 , what is the degree of (f o g)(x)
pishuonlain [190]

Answer D

...........................................

6 0
3 years ago
A student would like to estimate the proportion of the senior class that plans to attend prom this year. The student goes to the
Paul [167]

Answer:

No, although the random and large counts conditions are met, the 10% condition is not met.

Step-by-step explanation:

The random condition is met because the student selects a random sample of 50 seniors. The large counts condition is met because there are 38 expected successes and 12 expected failures, which are both at least 10. The 10% condition is not met because n = 50 is not less than 10% of the size of the population (N = 274 seniors).

3 0
4 years ago
Which of the following is the best approximation of the correlation coefficient for the data displayed in the scatterplot?
ra1l [238]

Answer:

0.5

Step-by-step explanation:

8 0
3 years ago
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