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Radda [10]
3 years ago
8

What is the product?

Mathematics
2 answers:
xxMikexx [17]3 years ago
7 0

Answer:

{ \tt{(5r - 4)( {r}^{2} - 6r + 4) }} \\  = {  \tt{( {5r}^{3}  -  {30r}^{2}  + 20r - 4 {r}^{2} + 24r - 16) }} \\  = { \tt{ {5r}^{3} - 34 {r}^{2}  + 44r - 16 }}

Vladimir [108]3 years ago
7 0

Answer:

5r³ - 34r² + 44r - 16

Step-by-step explanation:

\small \sf \: (5r − 4)(r² − 6r + 4)

use the distributive property

5r × (r² − 6r + 4) - 4× (r² − 6r + 4)

5r³ - 30r² + 20r - 4r² + 24r - 16

combine like terms

5r³ - 30r² - 4r² + 20r + 24r - 16

5r³ - 34r² + 44r - 16

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