The <span>isosceles triangle has two congruent sides
Their lengths are (</span> x + 3.8 ) and <span>16
Equate them :
x+3.8=16
Solve for x:
3=16-3.8=12.2
</span>
<span>The vertex of the parabola is the highest or lowest point of the graph.
</span><span>y=-4x^2+8x-12 = -4 (x^2 -2x +3)
Lets work with this now: </span>x^2 -2x +3
x^2 -2x +3 -> what is the closeset perfect square?
x^2 -2x +1 = (x-1)^2
So
x^2 -2x +3 = (x-1)^2 +2
Replacing to original
y=-4x^2+8x-12 = -4 (x^2 -2x +3) = -4 ((x-1)^2 +2) = -4 (x-1)^2 - 8
The min or max point is where the squared part = 0
So when x=1 , y= -4*0-8=-8
This will be the max of the parabola as there is - for the highest factor (-4x^2)
The max: x=1, y= -8
Mya took out money from the bank. When she went to get a bank statement she saw she had a $-2.00 in her account but she needed the number so she took out $30. So you would do $30+(-2.00)=(-32.00)
Step-by-step explanation:
3x+8<4x−12
Move all terms containing x
to the left side of the inequality.
Tap for more steps...
−x+8<−12
Move all terms not containing x
−x<−20
x>20
Interval Notation:(20,∞)
