Answer:
(i) The length of AC is 32 units, (ii) The length of BC is 51 units.
Step-by-step explanation:
(i) Let suppose that AB and BC are collinear to each other, that is, that both segments are contained in the same line. Algebraically, it can be translated into this identity:
If we know that 
and 
, then:
The length of AC is 32 units.
(ii) Let suppose that AB and AC are collinear to each other, that is, that both segments are contained in the same line. Algebraically, it can be translated into this identity:
If we know that 
and 
, then:
The length of BC is 51 units.
A. -(a+5)
Because the negative sign is outside the parenthesis, multiplying by -1 just removes the negative sign:
-(a+5) * -1 = a+5
B. -(-x+31)
Apply the distributive property:
-(-x+31) becomes (- -x +31) which simplifies to (x+31)
multiply that by -1 to get -x+31
C. -(4x+12)
Because the negative sign is outside the parenthesis, multiplying by -1 just removes the negative sign:
-(4x+12) * -1 = 4x+12
11x+3y=103 and y=3x+1.
11x+3(3x+1)=103 -----> plug in (3x+1) for y in the first equation. You will want to distribute the 3 to the 3x+1 to get something that looks like:
11x+9x+3=103 ------> now you want to combine like terms
20x+3=103 ---> subtract 3 from both sides
20x=100 ----> divide both sides by 20
x=5
y=3(5)+1 ---> I like to plug in this to the equation that already has y isolated. 3*5 is 15, add 1 and you find that y=16.
(5, 16) will be your final answer (:
Move (-5)^-6 to the numerator
Multiply (-5)^5 and (-5)^-6 by adding the exponents and you would get (-5)^11
Then raise -5 to the 11th power and you would get −48828125
