Answer:
Incomplete question
First aspect of the question is typed below.
The shape of the distribution of the time required to get an oil change at a 20-minute oil-change facility
is unknown. However, records indicate that the mean time is 2l.2-minutes, and the standard deviation 3.5 minutes.
Explanation:
Employees bonus $50
35 oil changes between 10:00 am to 12:00pm
n = 35
10% changes
So, the z - score can be calculated using
z-score = InvNorm(0.10)
z-score = -1.28
So, given that,
Standard deviation is 3.5minutes
σ = 3.5 minutes
Mean time is 21.2 minutes
μx = 21.2 minutes
Then,
σx = σ / √n
σx = 3.5 / √35
σx = 0.5916 minutes
Then, Z score can be written as
Z = (x - μx) / σx
-1.28 = (x - 21.2) / 0.5916
Cross multiply
-1.28 × 0.5916 = x - 21.2
-0.7573 = x - 21.2
x = 21.2 - 0.7573
x = 20.443 minutes
There is a 10% chance of being at or below a mean oil-change time of 20.44 minutes
Answer:
A. economies of scale.
Explanation:
The economies of scale is the scale where the company has the advantage of the cost that reaped by the organization in the case when there is an efficient production. It could be accomplished when the level of production or the volume of the production rises by lowering the cost
Therefore as per the given situation, the option A is correct as it fits to the current situation
Hence, the correct option is A.
Answer:
Then the constant increases?