Any of 9's multiples besides 9 and 18 will work.
So: 27, 35, 45, 54 ,63, 72, 81, 90, 99, 108, 117, 126, 135, and so on
Answer:
1) x=8, y=138
2) x=110
Step-by-step explanation:
Answer:
B. x^1/8 y^8
Step-by-step explanation:
here are the steps so you understand better
We can write this as:-
P(x) = + x^3 - 5x^2 - 25x + 125
There are 2 changes of real sign so by Descartes Rule of signs there are either 2 positive real roots or 0 positive roots.
P(-x) = - x^3 - 5x^2 + 25x + 125
There is just one change of sign so there is exactly 1 real negative root.
125 is a multiple of 5 so By rational root theorem 5 could be a positive root.
P(5) = 125 - 125 - 125 + 125 = 0 so one zero is 5
if we divide the polynomial by (x - 5) we get the quadratic
x^2 - 25
(x + 5)(x - 5) = 0
x = 5,-5
so the roots are 5 (multiplicity 2) and -5.
2 real positive zeroes and one real negative zero
That looks very hard, keep trying with the steps so yeah
