When the velocity goes from 40km/h to 20 km/h, the kinetic energy decreases by a factor of 4.
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What happens to the kinetic energy?</h3>
We know that the kinetic energy depends of the square of the velocity. Thus, if we decrease the velocity from 40km/h to 20km/h, then the kinetic energy decreases.
Remember that the kinetic energy is:
K = (m/2)*v²
Where m is the mass.
The initial kinetic energy is:
K = (m/2)*(40km/h)²
The final kinetic energy is:
K' = (m/2)*(20km/h)²
The quotient gives:
K/K' = [ (m/2)*(40km/h)²]/[ (m/2)*(20km/h)²]
K/K' = (40km/h)²/(20km/h)² = 4
So the kinetic energy decreases by a factor of 4.
Learn more about kinetic energy:
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Answer:
It could be a solution
Step-by-step explanation:
This depends on what equation you are solving. It could be a solution for a quadratic or even a transformation problem.
4.16 is the simplified version of 25/6 and 4.16÷45/2+(2/3)^2·1/30 i believe is 0.18 because first you have to simplify the 2/3^2(the exponent) which changes the equation to 4.16÷45/2+<u>4/9</u>·1/30. Then you have to multiply the 4/9 by 1/30 which equals 2/135 and changes the equation to 4.16÷45/2+2/135. The add 45/2+2/135 to make 6079/270 and changes the equation to 4.16÷6076/270. The last step is to divide the equation which makes 0.18 :)
What were you thinking about when you were writing this book