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NeX [460]
3 years ago
6

What are the features of the quadratic function f(x) = x^2 + 10x + 21?

Mathematics
1 answer:
defon3 years ago
3 0

A is the correct answer buddy.

_________________________________

good luck.♥️♥️♥️♥️♥️

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The diagonals of a square are _____ each other
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Answer: d) perpendicular bisectors of

Step-by-step explanation:

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Your having lunch at Taco Bell. You have your choice of a taco,burrito or Mexican pizza. You can choose between rice and beans.
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Let T be the taco, B the burrito, MP the mexican pizza, R the rice, and N the beans.

For the main course we can have the first three.

----- T

------ B

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Each main course comes with the two sides. So an R branch and a B branch go to each of the taco, burrito, or pizza.

-----T---------R or N.

We expand it to

--------T-----------R

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And we repeat it for the rest.


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3 years ago
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A new book is being planned. it will have 24 pages of introduction. then it will have c 12-page chapters and 48 more pages at th
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3 0
3 years ago
A wheel has a diameter of 28 inches. What is the approximate distance around the outside of the wheel? Use 3.14 for pi.
prohojiy [21]

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43.96

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8 0
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During halftime of a basketball ​game, a sling shot launches​ T-shirts at the crowd. A​ T-shirt is launched from a height of 4 f
Sonbull [250]

Answer:

(a) The time the T-shirt takes to maximum height is 2 seconds

(b) The maximum height is 68 ft

(c) The range of the function that models the height of the T-shirt over time given above is 4 + 64\cdot t - 16 \cdot  t^{2}

Step-by-step explanation:

Here, we note that the general equation representing the height of the T-shirt as a function of time is

h = h_1 + u\cdot t - \frac{1}{2} \cdot g  \cdot  t^{2}

Where:

h = Height reached by T-shirt

t = Time of flight

u = Initial velocity = 64 ft/s

g = Acceleration due to gravity (negative because upward against gravity) = 32 ft/s²

h₁ = Initial height of T-shirt = 4 ft

(a) The maximum height can be found from the time to maximum height given as

v = u - gt

Where:

u = Initial velocity = 64 ft/s

v = Final upward velocity at maximum height = 0 m/s

g = 32 ft/s²

Therefore,

0 = 64 - 32·t

32·t = 64 and

t = 64/32 = 2 seconds

(b) Therefore, maximum height is then

h = 4 + 64\times 2 - \frac{1}{2} \times 32  \times  2^{2}

∴ h = 68 ft

The T-shirt is then caught 41 ft above the court on its way down

(c) The range of the function that models the height of the T-shirt over time given above is derived as

h = h_1 + u\cdot t - \frac{1}{2} \cdot g  \cdot  t^{2}

With u = 64 ft/s

g = 32 ft/s² and

h₁ = 4 ft

The equation becomes

h =4 + 64\cdot t - \frac{1}{2} \times 32  \cdot  t^{2} = 4 + 64\cdot t - 16 \cdot  t^{2}.

6 0
3 years ago
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