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1 year ago

Am object of ma 4 i thrown vertically upward from level ground with initial peed of 20. How high did the object go

Physics

1 answer:

denis23 [38]1 year ago

8 0

The maximum height of the object when thrown at the speed of 20 m/s is 20 m.

What is speed?

Speed is the magnitude of the rate of change of the position of any object with time which is a scalar quantity. It is the ratio of speed by time with the unit m/s or cm/s.

The height this object can travel with initial speed of 20 m/s can be calculated as,

where v is the final velocity, u is the initial velocity a is the acceleration due to gravity s is height.

0 = 20^2 + 2 (-10) s

s = 400 / 20 = 20 m

Therefore, the maximum height the object can travel with initial speed of 20 m/s is 20m.

To learn more about the speed click on the given link brainly.com/question/13943409

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Describe what happens to the particles of water when it boils.

Nezavi [6.7K]

Answer:

The liquid turns to a gas.

Explanation:

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3 years ago

Lasers can be constructed that produce an extremely high intensity electromagnetic wave for a brief time—called pulsed lasers. T

alex41 [277]

Answer:

30643 J

Explanation:

$\mu_0$ = Vacuum permeability = $4\pi \times 10^{-7}\ H/m$

t = Time taken = 1 ns

c = Speed of light = $3\times 10^8\ m/s$

$E_0$ = Maximum electric field strength = $1.52\times 10^{11}\ V/m$

A = Area = $1\ mm^2$

Magnitude of magnetic field is given by

$B_0=\dfrac{E_0}{c}\\\Rightarrow B_0=\dfrac{1.52\times 10^{11}}{3\times 10^8}\\\Rightarrow B_0=506.67\ T$

Intensity is given by

$I=\dfrac{cB_0^2}{2\mu_0}\\\Rightarrow I=\dfrac{3\times 10^8\times 506.67^2}{2\times 4\pi \times 10^{-7}}\\\Rightarrow I=3.0643\times 10^{19}\ W/m^2$

Power, intensity and time have the relation

$E=IAt\\\Rightarrow E=3.0643\times 10^{19}\times 1\times 10^{-6}\times 1\times 10^{-9}\\\Rightarrow E=30643\ J$

The energy it delivers is 30643 J

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3 years ago

The minimum frequency of light needed to eject electrons from a metal is called the threshold frequency, ν0. find the minimum en

shusha [124]

The energy carried by the incident light is
$E=hf$
where h is the Planck constant and f is the frequency of the light. The threshold frequency is the frequency that corresponds to the minimum energy needed to eject the electrons from the metal, so if we substitute the threshold frequency in the formula, we get the minimum energy the light must have to eject the electrons:
$E=hf=(6.63 \cdot 10^{-34}Js)(5.64 \cdot 10^{14}s^{-1})=3.74 \cdot 10^{-19}J$