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ehidna [41]
2 years ago
15

Am object of ma 4 i thrown vertically upward from level ground with initial peed of 20. How high did the object go

Physics
1 answer:
denis23 [38]2 years ago
8 0

The maximum height of the object when thrown at the speed of 20 m/s is 20 m.

What is speed?

Speed is the magnitude of the rate of change of the position of any object with time which is a scalar quantity. It is the ratio of speed by time with the unit m/s or cm/s.

The height this object can travel with initial speed of 20 m/s can be calculated as,

<u>v^2 = u^2 + 2as</u>

where v is the final velocity, u is the initial velocity a is the acceleration due to gravity s is height.

0 = 20^2 + 2 (-10) s

s = 400 / 20 = 20 m

Therefore, the maximum height the object can travel with initial speed of 20 m/s is 20m.

To learn more about the speed click on the given link brainly.com/question/13943409

#SPJ4

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Compare the weight of a 5.00-kg object on Earth’s surface to the gravitational force between a 5.00-kg object that is one Earth
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Answer

given,

mass of an object = 5 Kg

mass of the other object = 5.98 x 10²⁴ Kg

radius of earth = 6371 Km = 6.371 x 10⁶ m

comparison between gravitational force between two object and weight of the object.

gravitational force between two objects

   F = \dfrac{Gm_1m_2}{r^2}

   F = \dfrac{6.67 \times 10^{-11}\times 5 \times 5.98 \times 10^{24}}{(6.371 \times 10^6)^2}

      F = 49.134 N

weight of the object on the earth surface

  F = m g

  F = 5 x 9.81

  F = 49.05 N

From the above two calculation we can conclude that gravitational force is approximately equal to weight of the body.

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3 years ago
If you were in a storm, you would need to know the speed at which its moving true or false
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(PLEASE HELP) Which of the following is the name for two or more types of atoms that are chemically bonded together?
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Near the surface of Earth an electric field points radially downward and has a magnitude of approximately 100 N/C. What charge (
pentagon [3]

Answer:

q=2.997\times 10^{-4}C

Sign-Negative

Explanation:

We are given that

Electric field =E=100NC^{-1} (Radially downward)

Acceleration=0.19 ms^{-2}(Upward)

Mass of charge=3 g=3\times 10^{-3}kg

1kg=1000g

We have to find the magnitude and sign of  charge would have to be placed on a penny .

By newton's second law

\sum F_y=ma

\sum F_y=qE-mg

Substitute the values then we get

qE-mg=ma

Substitute the values then we get

q(100)-3\times 10^{-3}(9.8)=3\times 10^{-3}(0.19)

100q-29.4\times 10^{-3}=0.57\times 10^{-3}

100q=0.57\times 10^{-3}+29.4\times 10^{-3}=29.97\times 10^{-3}

q=\frac{29.97\times 10^{-3}}{100}

q=2.997\times 10^{-4}C

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Because electric force acting  in opposite direction of electric field therefore,charge on penny will be negative.

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