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tensa zangetsu [6.8K]
3 years ago
10

The resistance of the body varies from approximately 500 kΩ (when it is very dry) to about 1.00kΩ (when it is wet). The maximum

safe current is about 5.00 mA. At 10.0mA or above, muscle contractions can occur that may be fatal.
a)What is the largest potential difference that a person can safely touch if his body is wet?

b)Is this result within the range of common household voltages?
Physics
1 answer:
Nady [450]3 years ago
4 0

Answer:

you absolute buffoon Use Ohms' Law:   V = RI

V = (1x10^3)(5x10^-3) = 5 volts

Yes, this is in the range of normal household voltages.  

Explanation:

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A certain electromagnetic wave traveling in seawater was observed to have an amplitude of 98.02 (V/m) at a depth of 10 m, and an
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Answer:

The  value is   \alpha =  0.002 Np/m

Explanation:

From the question we are told that

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   The second amplitude is  E_{max}2 =  81.87 \  (V/m)

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Generally from the spatial wave equation we have

   v(x) =  Ae^{-\alpha d}cos(\beta x  + \phi_o)

=>       \frac{v(x)}{v(x)} =\frac{  Ae^{-\alpha d}cos(\beta x  + \phi_o)}{ Ae^{-\alpha d}cos(\beta x  + \phi_o)}

So considering the ratio of the equation for the  two depth

\frac{A}{A_S}  =  \frac{e^{-D_1 \alpha }}{e^{-D_2 \alpha }}

=>   \frac{98.02}{81.87}  =  \frac{e^{-10 \alpha }}{e^{-100 \alpha }}

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4 0
3 years ago
Tell me the answer please
STatiana [176]

Answer:

transverse wave is the answer

7 0
2 years ago
Read 2 more answers
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