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Elodia [21]
3 years ago
5

What is the half-life of a radioisotope

Physics
2 answers:
IceJOKER [234]3 years ago
4 0
The rate at which a radioactive isotope<span> decays is measured in </span>half-life. The termhalf-life<span> is defined as the time it takes for one-</span>half<span> of the atoms of a radioactive material to disintegrate. </span>Half-lives<span> for various </span>radioisotopes<span> can range from a few microseconds to billions of years.</span>
HACTEHA [7]3 years ago
4 0

Answer:

It is the time after which a given sample of radioactive substance will decay to half of the initial number present in the sample.

Explanation:

As we know that as per law of radioactivity the number of radioactive nuclei present in the sample is proportional to the rate of decay

so it is given by

\frac{dN}{dt} = -\lambda N

after solving above relation we will have

N = N_0e^{-\lambda t}

now here we know that as the number of nuclei is reduced to half of the initial number then we have

\frac{N_0}{2} = N_0e^{-\lambda t}

t = \frac{ln2}{\lambda}

so this time is known as half life where the denominator of the equation is known as decay constant.

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Answer:

the resulting temperature is 23.37 ⁰C

Explanation:

Given;

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heat lost by the hot iron = heat gained by the water

m_1c_1 \Delta t_1 = m_2c_2\Delta t_2\\\\m_1c_1 (100 - T) = m_2c_2 (T- 20)\\\\0.08 \times 462 (100-T) = 0.2 \times 4,200 (T-20)\\\\36.96 (100-T) = 840 (T-20) \\\\100 - T = 22.72 (T-20)\\\\100-T = 22.72 T - 454.4 \\\\554.4 = 23.72T\\\\T = \frac{554.4}{23.72} \\\\T = 23.37 \ ^0C

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