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Elodia [21]
3 years ago
5

What is the half-life of a radioisotope

Physics
2 answers:
IceJOKER [234]3 years ago
4 0
The rate at which a radioactive isotope<span> decays is measured in </span>half-life. The termhalf-life<span> is defined as the time it takes for one-</span>half<span> of the atoms of a radioactive material to disintegrate. </span>Half-lives<span> for various </span>radioisotopes<span> can range from a few microseconds to billions of years.</span>
HACTEHA [7]3 years ago
4 0

Answer:

It is the time after which a given sample of radioactive substance will decay to half of the initial number present in the sample.

Explanation:

As we know that as per law of radioactivity the number of radioactive nuclei present in the sample is proportional to the rate of decay

so it is given by

\frac{dN}{dt} = -\lambda N

after solving above relation we will have

N = N_0e^{-\lambda t}

now here we know that as the number of nuclei is reduced to half of the initial number then we have

\frac{N_0}{2} = N_0e^{-\lambda t}

t = \frac{ln2}{\lambda}

so this time is known as half life where the denominator of the equation is known as decay constant.

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If a range hood removes contaminants at a flow rate of F liters of air per​ second, then the percent P of contaminants that are
podryga [215]

Explanation:

The given value of P is as follows.

           P = 1.06F + 22.18,           10 \leq F \leq 70

or,       P' = 1.06

As p' is defined and non-zero. Hence, only critical points are boundary points.

For F = 10, the value of P will be calculated as follows.

         P = 1.06 \times 10 + 22.18

            = 32.78

For F = 70, the value of P will be calculated as follows.

        P = 1.06 \times 70 + 22.18

           = 96.38

Therefore, the minimum value of P is 32.78 and maximum value of P is 96.38.

3 0
3 years ago
Marvin Martian is standing on planet Potatoine.
prisoha [69]

Answer:

W = 113.98 N

Explanation:

Given that,

Radius of PotatoineR=6.4\times 10^6\ m

Mass of Potatoine, M=2\times 10^{24}\ kg

Mass of Marvin, m = 35 kg

We need to find his weight on Potatoine. Weight of an object is given by :

W = mg

g is acceleration due to gravity, g=\dfrac{GM}{R^2}

So,

W=\dfrac{GMm}{R^2}\\\\W=\dfrac{6.67\times 10^{-11}\times 35\times 2\times 10^{24}}{(6.4\times 10^6)^2}\\\\W=113.98\ N

So, his weight on Potatoine is 113.98 N.

4 0
3 years ago
if you push a box a distance of 2000 meters with a force of 1 newton, how many calories have you used
kap26 [50]
Note that
1 J = 0.239 cal

By definition,
Work = Force x Distance

Therefore work done is
W = (1 N)*(2000 m) = 2000 J

In calories,
W = (2000 J)*(0.239 cal/J) = 478 cal

Answer: 478 calories

4 0
3 years ago
A car with mass 450 kg has a kinetic energy of 16,256 j. What is the speed of the car?
Vikentia [17]
Do you still need the answer ?
7 0
3 years ago
Each of three tuning forks, A, B, and C, has a slightly different frequency. When A and B are sounded together, they produce a b
a_sh-v [17]

Answer:

The smallest possible beat frequency when B and C are sounded together is 3 Hz

Explanation:

Given;

the beat frequency of A and B = 2 Hz

the beat frequency of A and C = 5 Hz

Beat frequency is equal to the difference in frequency of the two notes that interfere to produce the beats.

F_b_{(AB)} = 2 \ Hz\\\\F_A - F_B = 2 \ Hz -----equation(1)\\\\F_b_{(AC)} = 5 \ Hz\\\\F_A - F_C = 5 \ Hz-----equation(2)\\\\from \ equation(1), make \ F_A \ the \ subject \ of \ the \ formula\\\\F_A = 2H_z + F_B -----equation (3)\\\\Substitute \ in \ the \ value \ of \ F_A \ in \ equation(3) \ into \ equation(2)\\\\2H_z + F_B - F_C = 5H_z\\\\F_B-F_C = 5H_z - 2H_z\\\\F_B -F_C = 3Hz

Therefore, the smallest possible beat frequency when B and C are sounded together is 3 Hz

7 0
3 years ago
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