I’m sorry if i took up a lot of space, hope this is a valid approximate answer
Answer:
Restoring force of the spring is 50 N.
Explanation:
Given that,
Spring constant of the spring, k = 100 N/m
Stretching in the spring, x = 0.5 m
We need to find the restoring force of the spring. It can be calculated using Hooke's law as "the force on a spring varies directly with the distance that it is stretched".


F = 50 N
So, the restoring force of the spring is 50 N. Hence, this is the required solution.
The solution is 22 2(n+3)-4&6
Answer:
49N
Explanation:
F=ma
We know the mass is 5kg, and since the ball is suspended on one cable, the acceleration is g, 9.8m/s^2
F=5kg*9.8m/s^2
= 49N
Hope this helps!