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zmey [24]
3 years ago
5

An object that allows almost all that light that strikes it to pass through and that forms a clear image is

Chemistry
1 answer:
ra1l [238]3 years ago
5 0

Answer: the object is transparent.

Explanation:

let me know if this helps

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What differentiates one element from another
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1. How are Cotton, Nylon and Wool different ?<br><br> 2. How are Cotton, Nylon and Wool similar ?
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Read 2 more answers
Estimate ΔG°rxn for the following reaction at 775 K. 2Hg(g) + O2(g) → 2HgO(s) ΔH°= -304.2 kJ; ΔS° = -414.2 J/K
hichkok12 [17]

Answer:

\Delta G^0_{rxn}=16.81kJ

Explanation:

Hello!

In this case, since the Gibbs free energy of any process is related with the enthalpy change, temperature and entropy change as shown below:

\Delta G^0=\Delta H^0-T\Delta S^0

For a chemical reaction it is simply modified to:

\Delta G^0_{rxn}=\Delta H^0_{rxn}-T\Delta S^0_{rxn}

Thus, since the enthalpy of reaction is given as -304.2 kJ and the entropy as -414.2 J/K (-0.4142 kJ/K), at 775 K the Gibbs free energy of reaction turns out:

\Delta G^0_{rxn}=-304kJ-775K*(-0.4142\frac{kJ}{K} )\\\\\Delta G^0_{rxn}=16.81kJ

Whose result means this is a nonspontaneous reaction.

Best regards!

3 0
3 years ago
If the mass percentage composition of a compound is 72.1% Mn and 27.9% O, its empirical formula is
mojhsa [17]

Answer:

MnO- Manganese Oxide

Explanation:

Empirical formula: This is the formula that shows the ratio of elements

present in a  

compound.

   

How to determine Empirical formula

1. First arrange the symbols of the elements present in the compound

alphabetically to  determine the real empirical formula. Although, there

are exceptions to this rule, E.g H2So4

2. Divide the percentage composition by the mass number.

3. Then divide through by the smallest number.

4. The resulting answer is the ratio attached to the elements present in

a compound.

           

                                                                              Mn                         O    

                         

% composition                                                      72.1                      27.9    

                       

Divide by mass number                                       54.94                     16  

                                 

                                                                               1.31                      1.74    

                       

Divide by the smallest number                         1.31                      1.31                          

                                                                               1                    1.3

                                                 

The resulting ratio is 1:1

 

Hence the Empirical formula is MnO, Manganese oxide

8 0
4 years ago
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