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serg [7]
3 years ago
15

What differentiates one element from another

Chemistry
1 answer:
worty [1.4K]3 years ago
8 0
I think the number of protons in the nucleus the number of valence electrons atomic mass... 
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For the reaction shown, calculate how many moles of NO2 form when each amount of reactant completely reacts.
Anton [14]

Answer:-  2.4 mol NO_2 .

Solution:- It asks to calculate the moles of NO_2 formed when 1.2 moles of N_2O_5 are reacted.

There is 2:4 mol ratio between N_2O_5 and NO_2 . So, the moles of reactant are multiplied by the mol ratio to get the moles of NO_2 . The calculations are shown below:

1.2mol N_2O_5(\frac{4mol NO_2}{2mol N_2O_5})

= 2.4 mol NO_2

So, 2.4 moles of NO_2 are formed when 1.2 moles of  N_2O_5 were reacted.

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3 years ago
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rosijanka [135]

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7 0
3 years ago
What the atmosphere mean
Alex_Xolod [135]
The envelope of gases surrounding the earth or another planet.
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3 years ago
The activation energy for a(n) _____ is quite large and usually takes extra energy from the environment, it is normally not a na
Ira Lisetskai [31]

Answer:

The activation energy for an endothermic reaction is quite large and usually takes extra energy from the environment, it is normally not a natural spontaneous process.

Explanation:

  • Endothermic reactions require absorbing energy of the surrounding mainly in the form of heat.
  • Chemical energy needs energy input to break the bonds.
  • Examples of endothermic reactions: Photosynthesis , melting of ice , and evaporating liquid water.
3 0
2 years ago
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Calculate the percentage of each element in acetic acid, hc2h3o2, and glucose, c6h12o6.
My name is Ann [436]
<em>Acetic acid, HC2H3O2</em>

First, calculate for the molar mass of acetic acid as shown below.
    M = 1 + 2(12) + 3(1) + 2(16) = 60 g

Then, calculating for the percentages of each element.
<em> Hydrogen:</em>
    P1 = ((4)(1)/60)(100%) = <em>6.67%</em>

<em> Carbon:</em>
   P2 = ((2)(12)/60)(100%) = <em>40%</em>

<em>Oxygen</em>
  P3 =((2)(16) / 60)(100%) = <em>53.33%</em>

<em>Glucose, C6H12O6</em>

The molar mass of glucose is as calculated below,
   6(12) + 12(1) + 6(16) = 180

The percentages of the elements are as follow,
 <em> Hydrogen:</em>
   P1 = (12/180)(100%) = <em>6.67%</em>

<em>Carbon:</em>
  P2 = ((6)(12) / 180)(100%) = <em>40%</em>

<em>Oxygen:</em>
  P3 = ((6)(16) / 180)(100%) = <em>53.33%</em>

b. Since the empirical formula of the given substances are just the same and can be written as CH2O then, the percentages of each element composing them will just be equal. 
6 0
3 years ago
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