The factor which determines whether or not goods should be included in a physical count of inventory is

What is the fau and emergency management department’s campaign slogan?.

Aleks04 [339]

FAU and emergency management department’s campaign slogan is “FAU ALERT” or “ATTENTION FAU”. Read below about the usage of the slogan.

<h3>How does FAU use their slogan?</h3>

“ATTENTION FAU” is only utilised in messaging if an incident has the potential to suspend normal operations or affect life safety and/or destruction of University resources.

Therefore, the slogan is as provided above.

learn more about FAU: brainly.com/question/16054173

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3 0

2 years ago

"Stock R has a beta of 1.5, Stock S has a beta of 0.75, the required return on an average stock is 10%, and the risk-free rate o

Kaylis [27]

Answer:

4.5%

Explanation:

Stock R (Beta) = 1.5

Stock S (Beta) = 0.75

Expected rate of return on an average stock (Rm)= 10%

Risk free rate (Rf) = 4%

Required Return (Re) = Rf +(Rm-Rf) B

Required Return = 0.04 + (0.10-0.04) B

Required Return = 0.04 + 0.06B

Stock R = 0.04 + (0.06 * 1.50)

Stock R = 0.04 + 0.09

Stock R = 0.13

Stock R = 13%

Stock S = 0.04 + (0.06 * 0.75)

Stock S = 0.04 + 0.045

Stock S = 0.085

Stock S = 8.5%

Here, the more risky stock is R and less risky stock is S. Since, R has more beta than the Stock S.

= 13% - 8.5%

= 4.5%

7 0

3 years ago

Marla, the new accountant, impressed the interview committee because she graduated at the top of her class. the department super

Stells [14]

This is the Halo Effect

5 0

3 years ago

A mining company owns two mines, each of which produces three grades (high, medium, and low) of ore. The company has a contract

sashaice [31]

Answer:

They should operate Mine 1 for 1 hour and Mine 2 for 3 hours to meet the contractual obligations and minimize cost.

Explanation:

The formulation of the linear programming is:

Objective function:

$C=200M_1+160M_2$

Restrictions:

- High-grade ore: $6M_1+2M_2\geq12$

- Medium-grade ore: $2M_1+2M_2\geq8$

- Low-grade ore: $4M_1+12M_2\geq24$

- No negative hours: $M_1,M_2\geq0$

We start graphing the restrictions in a M1-M2 plane.

In the figure attached, we have the feasible region, where all the restrictions are validated, and the four points of intersection of 2 restrictions.

In one of this four points lies the minimum cost.

Graphically, we can graph the cost function over this feasible region, with different cost levels. When the line cost intersects one of the four points with the lowest level of cost, this is the optimum combination.

(NOTE: it is best to start with a low guessing of the cost and going up until it reaches one point in the feasible region).

The solution is for the point (M1=1, M2=3), with a cost of C=$680.

The cost function graph is attached.

7 0

3 years ago

Pat invested a total of $3,000. Part of the money was invested in a money market account that paid 10 percent simple annual inte

adell [148]

Answer:

$800 in account that pays 10% interest

$2,200 in account that pays 8% interest

Explanation:

Account A = Money market account that paid 10% simple annual interest

Account B = Money market account that paid 8% simple annual interest

W1 = Proportion of money invested in Account A

W2 = Proportion of money invested in Account B

W1 + W2 = 1

therefore, W1 = 1 - W2

Principle amount = $3,000

3000 x W1 = Amount of money invested in Account A

3000 x W2 = Amount of money invested in Account B

Total interest earned = $256

R1 = 10% simple interest on Account A

R2 = 8% simple interest on Account B)

Total Interest = (Principle x W1 x R1) + (Principle x W2 x R2)

256 = (3000 x W1 x 10%) + (3000 x W2 x 8%)

256 = 300 W1 + 240 W2

256 = 300 W1 + 240 ( 1 - W1)

256 = 300 W1 + 240 - 240 W1

16 = 60 W1

W1 = 16 / 60

W2 = 1 - W1 = 1 - (16/60) = 11/15

Amount of money invested in Account A = 3000 x W1 = 3000 x (16/60) = $800

Amount of money invested in Account B = 3000 x W2 = 3000 x (11/15) =$2,200

6 0

3 years ago