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guapka [62]
2 years ago
10

How do u solve what is unit price for a PIECE of cheese if 124 pounds cost 11.25

Mathematics
1 answer:
Yanka [14]2 years ago
5 0
Then it is $19:99 per chesse piece
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Supervisor a earns a flat rate of $25 per hour, while supervisor b earns $20 per hour for the first 30 hours and then 50% more f
jek_recluse [69]
A: 25h
b:20h+30(h-30)
25h=20h+30(h-30)
5h=30h-30^2
-25h=-30^2
25h=30^2
h=900/25
8 0
3 years ago
Read 2 more answers
What is the equation of the parabola passing through the points<br>(0,6). (3, 15.6), and (10,-4)?​
Novosadov [1.4K]

Answer:

y = -0.6x^2 + 5x + 6

Step-by-step explanation:

First, find the equation of a linear line that passes through the points (0,6) and (3, 15.6) in the slope intercept form, y = mx + b. We know that the line has a y-intercept of 6, so b = 6. Substitute 3 for x, 15.6 for y, and 6 for b to find m.

y = mx + b

15.6 = 3m + 6

9.6 = 3m

m = 3.2

y = 3.2x + 6

y = a(x - 0)(x - 3) + 3.2x + 6

y = a(x)(x - 3) + 3.2x + 6

Finally, substitute 10 for x and -4 for y in the equation above to find a.

-4 = a(10)(10 - 3) + 3.2*10 + 6

-4 = a(10)(7) + 32 + 6

-4 = 70a + 38

-42 = 70a

a = -0.6

Simplify to write in standard form.

y = -0.6(x)(x - 3) + 3.2x + 6

y = -0.6x^2 + 5x + 6

7 0
1 year ago
The price of a DVD movie was reduced from $20 to $18. By what percentage was the price of the DVD movie reduced? *
Alla [95]

Answer:

A. 10%

Step-by-step explanation:

First calculate how much percentage is in one dollar, which is 5% per dollar, then times that by how much money is deducted which is $2, and you will get your answer 10%.

Hope this helps good luck!

6 0
2 years ago
If it takes 6 hours for a plane to travel 720km with a tail wind and 8 hours to make the return trip with a head wind. Find the
denis-greek [22]

The speed of wind and plane are 105 kmph and 15 kmph respectively.

<u>Solution:</u>

Given, it takes 6 hours for a plane to travel 720 km with a tail wind and 8 hours to make the return trip with a head wind.  

We have to find the air speed of the plane and speed of the wind.

Now, let the speed wind be "a" and speed of aeroplane be "b"

And, we know that, distance = speed x time.

\text { Now, at tail wind } \rightarrow 720=(a+b) \times 6 \rightarrow a+b=\frac{720}{6} \rightarrow a+b=120 \rightarrow(1)

Now at head wind → 720=(a-b) \times 8 \rightarrow a-b=\frac{720}{8} \rightarrow a-b=90 \rightarrow(2)

So, solve (1) and (2) by addition

2a = 210

a = 105

substitute a value in (1) ⇒ 105 + b = 120

⇒ b = 120 – 105 ⇒ b = 15.

Here, relative speed of plane during tail wind is 120 kmph and during head wind is 90 kmph.

Hence, speed of wind and plane are 105 kmph and 15 kmph respectively.

6 0
3 years ago
PLZ HELP ME
Likurg_2 [28]

Answer:

x ≈ 14.87

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

x² = 10² + 11² = 100 + 121 = 221 ( take the square root of both sides )

x = \sqrt{221} ≈ 14.87 ( to the nearest hundredth )

8 0
2 years ago
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