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Zarrin [17]
3 years ago
14

Examine the pattern of numbers in the table , and find a formala for y in terms of x.

Mathematics
2 answers:
Vitek1552 [10]3 years ago
5 0

Answer:

y = x² + 4

Step-by-step explanation:

Observing the pattern, we can deduce that :

When x = 1, y = 1² + 4 = 5

When x = 2, y = 2² + 4 = 8

When x = 3, y = 3² + 4 = 13

When x = 4, y = 4² + 4 = 20

Therefore, we can generalise the pattern as :

y = x² + 4

lana66690 [7]3 years ago
4 0

Plotting the points could help you notice that they lie along a parabola. In particular, you can see that y is always 4 more than x^2.

So, the relation is

y=x^2+4

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50 points decreased by 26%
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26% of 50
26/100 * 50
13

50 - 13 = 37


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10. Please help. What is the length of ED⎯⎯⎯⎯⎯⎯⎯⎯?
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Answer:

The correct value is 12.

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What is the missing constant term in the perfect square that starts x^2+10x?
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There are 10 true-false questions and 20 multiple choice questions from which to choose a five-question quiz how many ways can t
beks73 [17]

Answer:

In 68229 ways can the quiz be selected such that there is atleast three multiple choice questions

Step-by-step explanation:

Given:

Number of True or false questions= 10

Number of multiple choice questions= 20

To Find:

How many ways can 5 questions can be selected if there must be at least three multiple choice questions =?

Solution:

Combination

A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter. In combinations, you can select the items in any order.  

The question States there sholud be ATLEAST 3 multiple choice question,

So, we may have

(3 Multiple choice question and 2 true or false question) or

(4 Multiple choice question and 1 true or false question) or

(5 Multiple choice question and 0 true or false question)

Required Number of ways = (20C3 X10C2) +(20C4 X10C1) + (20C5 X10C0)

Required Number of ways =(\frac{20!}{20!(20-3)!}\times\frac{10!}{10!(10-2)!})+(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-1)!}) +(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-0)!})

Required Number of ways = ( 1140 x 42) + (4845 x 10) +(15504 x 1)

Required Number of ways = 47880+48450+15504

Required Number of ways = 68229

3 0
3 years ago
Together, Tom and max have 72 football cards. Tom has 2 more than 4 times as many cards as max has. How many football cards does
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Tom has 58 football cards

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3 years ago
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