Answer:
a) Right 0≤p<π/2 and 3π/2<p≤2π
left π/2 ≤ p ≤3π/2
stopped p=π/2 and p=3π/2
b) 5.5cm and its final position (2π, 0)
c) 6.5cm
Step-by-step explanation:
we must find where the function becomes negative, positive and zero
(according to the graph)
the particle moves to the right where the function is positive
0≤p<π/2 and 3π/2<p≤2π , the particle moves to the left where the function is negative π/2 ≤ p ≤3π/2, and stopped p=π/2 and p=3π/2
s(t)=∫v(t)dt also s(t) = 5sin(t)
(according to the graph 2)
The displacement of the particle is 5.5 and its final position
(2π, 0)
The total displacement of the particle is 6.5
Answer:
Step-by-step explanation:
1. HI // KL , J is midpoint of HL 1. Given
2. ∠IHJ ≅ ∠JLK 2. Alternate interior angles are congruent
3. ∠IJH ≅ ∠KJL 3. Vertically opposite angles
4. HJ ≅ JL 4. Given
5. ΔHIJ ≅ ΔLKJ 5. A S A congruent
(Angle Side Angle)
Answer:
The answer would me 15m
Step-by-step explanation:
1. you multiply both of them together in order to get the area
L x W = A
Where/what slopes are I talking about?
Answer:
A = π(14t)²
Step-by-step explanation:
The radius is increasing at the rate of 14 cm per second.
We need to find the formula for the area A of the circle as the function of time t.
Initial area of the circle,
A = πr², where r is the radius of the circle
Area as a function of t will be :
A = π(14t)²
Here, 14t is the radius of the wave.
