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kipiarov [429]
4 years ago
6

Sara is a drummer in her school's marching band. She wants to make a geometrically similar model of a snare drum for her stuffed

animals. To find the dimensions she should use to make a cylindrical model with a scale of 1 : 4, Sara measures the radius and height of a snare drum and multiplies each dimension by . Which statement is true?
PLEASE HELP
Mathematics
1 answer:
Rom4ik [11]4 years ago
4 0

Answer: A cylinder with Sara’s dimensions will be geometrically similar, but the scale factor will be 1:2

Step-by-step explanation:

Here is the complete question:

Sara is a drummer in her school’s marching band. She wants to make a geometrically similar model of a snare drum for her stuffed animals. To find the dimensions she should use to make a cylinder model with a scale of 1:4, Sara measures the radius and height of a snare drum and multiplies each dimensions by 1/2, which statement is true?

A. a cylinder with Sara’s dimensions will be geometrically similar, and scale factor will be 1:4

B. A cylinder with Sara’s dimensions will be geometrically similar, but the scale factor will be 1:2

C. a cylinder with Sara’s dimensions will be geometrically similar, but the scale factor will be 1:8

D. a cylinder with sara’s dimensions will not be geometrically similar

The ratio 1:4 would be the same as when it was written asa fraction as 1/4. Then, she multiplied the dimensions by 1/2, this would be a ratio of 1:2

Then the answer is that a cylinder with Sara’s dimensions will be geometrically similar, and the scale factor will be 1:2

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a)  C=e^1=e

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c) E(X) =\int_{1}^e x \frac{1}{x} dx =x \Big|_1^e \ =e-1

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Step-by-step explanation:

a) what must the value of C be so that f(x) is a probability density function?

In order to be a probability function we need this condition:

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c) find E(X) and Var(X)

We can find the expected value on this way:

E(X) =\int_{1}^e x \frac{1}{x} dx =x \Big|_1^e \ =e-1

In order to find the Var(X) we need to find the second moment given by:

E(X^2) =\int_{1}^e x^2 \frac{1}{x} dx =\frac{x^2}{2} \Big|_1^e \ =\frac{1}{2}(e^2 -1)

And now we can use the following definition:

Var(X)=E(X^2)-[E(X)]^2= \frac{1}{2}(e^2 -1) -(e-1)^2 = 0.242

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