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Margaret [11]
3 years ago
8

Do the sides 4, 5, and 6 form a Pythagorean Triple?

Mathematics
2 answers:
OLEGan [10]3 years ago
7 0

Answer:

no

Step-by-step explanation:

A pythagorean triple is only formed by 3 sides

NemiM [27]3 years ago
3 0

Answer:

They do not form a Pythagorean Triple.

If it was a Triple,  4^2+5^2 should equal 6^2.

4^2+5^2=16+25=41

6^2=36

41≠26

It doesn't work, therefore it is not a Pythagorean Triple.

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Answer:

180° = pi radians

Step-by-step explanation:

360° = 2pi radians

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see image

180° is pi radians.

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I think it is 482...
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Answer:

6a

Step-by-step explanation:

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4 years ago
Can you please help me out
Taya2010 [7]

The bag contains,

Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,

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\text{Total marbles = (R) + (G) +(B) = 9 + 7 + 4 = 20 marbles}

Let P(R) represent the probablity of picking a red marble,

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P(B) represent the probability of picking a blue marble.

Probability , P, is,

\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}

Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,

That means once a marble is drawn, the total marbles (possible outcome) reduces as well,

\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}

Hence, the best option is G.

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1 year ago
Ms. Jaffey had a total of 428.5 ounces of pretzels to put into 5 bowls for a party. She put an equal number of ounces of pretzel
alekssr [168]
Multiply the 2 numbers and see what you get
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3 years ago
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