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shepuryov [24]
3 years ago
14

PLEASE HELP!!!

Mathematics
1 answer:
iogann1982 [59]3 years ago
7 0

Her new car costed $74,855.96

Step-by-step explanation:

Sara just bought a new car

  • This car cost $2,362.12 less than twice the price of her first car
  • She paid 38,609.04 dollars for her first car

we need to find how much her new car costed

∵ The cost of her first car = $38,609.04

∵ The cost of the new car is $2,362.12 less than twice the

   cost of her first car

- That means multiply the cost of the 1st car by 2 and then

   subtract 2,362.12 from the product

∴ The cost of the new car = 2(38,609.04) - 2,362.12

∴ The cost of the new car = 77218.08 - 2,362.12

∴ The cost of the new car = 74,855.96

Her new car costed $74,855.96

Learn more:

You can learn more about the word problems in brainly.com/question/10557938

#LearnwithBrainly

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Answer:

The simplified expression to the given expression is \frac{4x^6}{y^2}

Therefore \frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}=\frac{4x^6}{y^2}

Step-by-step explanation:

Given fractional expression is \frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}

To simplify the given expression as below :

\frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}

=\frac{2(2x^3y^4)^4}{(2x^2y^6)^3}

=\frac{2[(2)^4(x^3)^4(y^4)^4]}{(2)^3(x^2)^3(y^6)^3}  ( using the property (a^m)^n=a^{mn})

=\frac{2[(2)^4(x^{12})(y^{16})]}{(2)^3(x^6)(y^{18})}

=2[(2)^4(x^{12})(y^{16})](2)^{-3}(x^{-6})(y^{-18})  (  ( using the property a^m=\frac{1}{a^{-m}} )

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Therefore the simplified expression is \frac{4x^6}{y^2}

Therefore \frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}=\frac{4x^6}{y^2}

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Step-by-step explanation:

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