The statement is expressed algebraically as
(x/43) - 87 = -75
Answer:
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Step-by-step explanation:
Given the data in the question;
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is?
dA/dt = rate in - rate out
first we determine the rate in and rate out;
rate in = 3pound/gallon × 5gallons/min = 15 pound/min
rate out = A pounds/1000gallons × 5gallons/min = 5Ag/1000pounds/min
= 0.005A pounds/min
so we substitute
dA/dt = rate in - rate out
dA/dt = 15 - 0.005A
Therefore, If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Answer:
ok so first you add all the prices together.
$9:00+$7:00+$8:00+$6:00+$4:00=34
then divide 34 by the number of prices.
34/5
then you get the mean
$6.8 is the mean
Step-by-step explanation:
In scientific notation, it would be 2x10^3.
An easy trick to help remember when it is a multiple of 10 is that you do the numbers that aren't zero (2) times 10 and the exponent is how ever many zeros there are after the other numbers (3).
Answer:
The correct answer is :
Amount: 2
Base: 100
Percent: 2%
Step-by-step explanation:
So, we get the answer by using whatever we know. The first step is that 2 is the percent because it is having the percent sign . In addition we know that 100 is the base. And the one which is left is 2 so it's the amount.
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