Which long division problem can be used to prove the formula for factoring the difference of two perfect cubes?
1 answer:
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The complete square will be = 3
Step-by-step explanation:
Given,
or, [ by eliminating 2 from both the sides]
To make it square
or, [
or, = 9-6
or, = 3
Hence the correct option is B
I'll do a and e on the first one to show you how to do it
Then See if you can do the rest
a. 6(-3)<span><span>
</span></span>
When your multiplying or dividing with negative numbers; If one of your numbers is negative like the one above, your answer will be negative
So 6 × 3 = 18 ; but since there is a negative on the 3 your answer will be -18
e. -20 ÷ 5
same for this; 20 ÷ 5 = 4, but since the 20 is negative the answer will be <span>-4
You do b, c, d, and f on the first question. Tell me what you get and we'll go from there
</span>Now for the second question <span>
</span>I will do a and d to show you how to do this then you do the rest<span> (I'm inserting a picture with these)
</span>a.
First go ahead and turn the fractions into improper fractions, this makes them a bit easier to work with. When multiplying fractions; they do not need a common denominator, all you do is multiply top by top and bottom by bottom.<span>
However, when you add and subtract fractions you MUST have a common denominator
</span>d. (-4.25)(2) + (-4.25)(-2)
remember from the first problem a negative times a positive gives you a negative<span>
but when you times a negative by a negative you get a positive
Now you try b and c; let me know what you get, and we'll go from there!
</span>
Then See if you can do the rest
a. 6(-3)<span><span>
</span></span>
When your multiplying or dividing with negative numbers; If one of your numbers is negative like the one above, your answer will be negative
So 6 × 3 = 18 ; but since there is a negative on the 3 your answer will be -18
e. -20 ÷ 5
same for this; 20 ÷ 5 = 4, but since the 20 is negative the answer will be <span>-4
You do b, c, d, and f on the first question. Tell me what you get and we'll go from there
</span>Now for the second question <span>
</span>I will do a and d to show you how to do this then you do the rest<span> (I'm inserting a picture with these)
</span>a.
First go ahead and turn the fractions into improper fractions, this makes them a bit easier to work with. When multiplying fractions; they do not need a common denominator, all you do is multiply top by top and bottom by bottom.<span>
However, when you add and subtract fractions you MUST have a common denominator
</span>d. (-4.25)(2) + (-4.25)(-2)
remember from the first problem a negative times a positive gives you a negative<span>
but when you times a negative by a negative you get a positive
Now you try b and c; let me know what you get, and we'll go from there!
</span>