<span>2/5 : 4 halves in 2/ , and 10 halves in /5. each half = .5 in /2 but the denominator never changes. .5 x 4 = 20 in other words four .5's = 20. So the problem looks like this 20/5 but then you are forced to use the reciprocal of 20/5 which is 5/20 , now divide.</span>
Answer:
Step-by-step explanation:
2)f(x) = 2x² +4x - 3
a = 2 ; b = 4 ; c = -3
1) Put x = -1 in the equation
f(x) = 2*(-1)² + 4*(-1) -3 = 2 - 4 -3 = -5
Vertex = (-1,-5)
2) Upward
3) Minimum
4) axis of symmetry = -b/2a = -4/2*2=-4/4= -1
x = -1
5) domain: all real numbers (-∞ ,∞)
Range : y ≥ -5 ; [-5 , ∞)
3) f(x) = 3x² - 6x + 4
Vertex : (1,1)
Opening : upward
Minimum
Axis of symmetry: x = 1
Domain: all real numbers
Range: y ≥ 1 ; [1, ∞)
4)f(x) = -x² - 2x - 3
a) Vertex: f(x) = -(-1)² - 2*(-1) - 3 = -1 + 2 - 3 = -2
Vertex( -1,-2)
b) downward
c) Maximum
d) Axis of symmetry: x = 2/-2 = -1
x = -1
e) Domain: all real numbers
Range: y ≤ -2 ; (-∞ , -2]
5)f(x) = 2(x -2)²
a) Vertex: (2, 0)
b) Opening: upward
c) Minimum
d) x = 2
e)Domain: all real numbers
Range: y ≥ 0 ; [0,∞)
We know the CE = 10x + 18 and DE = 7x - 1 and D is the midpoint of CE
⇒ CE = 2 * DE
⇒ 10x + 18 = 2 * (7x - 1)
⇒ 10x + 18 = 14x - 2
⇒ -4x = -20
⇒ x = 5
Now we also know that BC = 9x - 3 and AC = CE = 10x + 18
⇒ AB = AC - BC
⇒ AB = 10x + 18 - (9x - 3)
⇒ AB = x + 21
Substituting the value of x,
⇒ AB = 5 + 21
⇒ AB = 26
Hence, the value of AB is 26 units.
Answer:
Step-by-step explanation:
