Answer:
if there is equivalent ratio cookies should be 48
Answer:
1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle
Step-by-step explanation:
Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is
V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³
the mass in that volume would be m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)
The density of an alpha particle is ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be
ρ= m/V
since both should be equal ρ=ρa , then
ρa= m/V =N*L/V → N =ρa*V/L
replacing values
N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg = 1.544*10⁹ Linebackers
N=1.544*10⁹ Linebackers
Dice have six sides. So 6 cubed would be 216. Does that sound right?
Answer:
Uche's pumping rate is <u>300 mL/s</u>.
Step-by-step explanation:
Given:
Uche pumps gasoline at a rate of 18 L/min.
Now, to find Uche's pumping rate in mL/s.
The rate at which Uche pumps gasoline = 18 L/min.
So, to get the pumping rate in mL/s we use convert L/min to mL/s by using conversion factor:
<u>1 L/min = 16.6667 mL/s.</u>
18 L/min = 16.6667 × 18 mL/s.
18L/min = 300 mL/s.
Therefore, Uche's pumping rate is 300 mL/s.
