Someone help me with this
2 answers:
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Answer:
"2.82" seems to be the correct solution.
Step-by-step explanation:
As we know,
A bag (Bag A) contains,
Red balls = 3
Blue ball = 1
A second bag (Bag B) contains,
Red balls = 1
Blue ball = 1
Now,
⇒ P(Bag A, red ball) =
On substituting the values, we get
⇒ =
⇒ =
Similarly,
Probability of second bag will be:
⇒ P(Bag B) =
hence,
In the first bag (Bag A), the expected number of red balls will be:
⇒
On substituting the values, we get
⇒
⇒
⇒
Answer:
<em>The probability is 0.89 or 89%</em>
Step-by-step explanation:
<u>Probability</u>
There are n=27 students in a certain Algebra 2 class. 18 out of them play basketball and 16 of them play baseball.
We also know 3 students play neither sport. This leaves 27-3=24 students playing sports.
The probability that a randomly chosen student plays basketball or baseball is:
Simplifying:
The probability is 0.89 or 89%