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Anvisha [2.4K]
3 years ago
5

The owner of a local nightclub has recently surveyed a random sample of n = 250 customers of the club. She would now like to det

ermine whether or not the mean age of her customers is over 30. If so, she plans to alter the entertainment to appeal to an older crowd. It not, no entertainment changes will be made. The appropriate hypothesis to test is:
Mathematics
1 answer:
seraphim [82]3 years ago
8 0

Answer:

The required hypothesis to test is H_0: \mu\leq 30 and H_1: \mu>30.

Step-by-step explanation:

Consider the provided information.

It is given that the nightclub has recently surveyed a random sample of n = 250 customers of the club.

She would now like to determine whether or not the mean age of her customers is over 30.

Null hypotheses is represents as H_0. Thus the null hypotheses is shown as:

H_0: \mu\leq 30

The alternative hypotheses is represents as H_1. Thus the alternative hypotheses is shown as:

H_1: \mu>30

Hence, the required hypothesis to test is H_0: \mu\leq 30 and H_1: \mu>30.

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3 years ago
I’m Really lost if I could get a answer it would be greatly appreciated
Nataly [62]
<h3>Answers:</h3>

f(g(x)) = \sqrt{x^2+5}+5\\\\g(f(x)) = x+30+10\sqrt{x-1}

================================================

Work Shown:

Part 1

f(x) = \sqrt{x-1}+5\\\\f(g(x)) = \sqrt{g(x)-1}+5\\\\f(g(x)) = \sqrt{x^2+6-1}+5\\\\f(g(x)) = \sqrt{x^2+5}+5\\\\

Notice how I replaced every x with g(x) in step 2. Then I plugged in g(x) = x^2+6 and simplified.

------------------

Part 2

g(x) = x^2+6\\\\g(f(x)) = \left(f(x)\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}+5\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}\right)^2+2*5*\sqrt{x-1}+\left(5\right)^2+6\\\\g(f(x)) = x-1+10\sqrt{x-1}+25+6\\\\g(f(x)) = x+30+10\sqrt{x-1}\\\\

In step 4, I used the rule (a+b)^2 = a^2+2ab+b^2

In this case, a = sqrt(x-1) and b = 5.

You could also use the box method as a visual way to expand out \left(\sqrt{x-1}+5\right)^2

6 0
3 years ago
What is the approximate area of the circle that fits perfectly inside of the square? Use Pi = 3.14 and round to the nearest tent
Pani-rosa [81]

Answer:

19.625\text{ cm}^2

Step-by-step explanation:

GIVEN: A square with base 5\text{ cm}, a circle that perfectly fits inside square.

TO FIND: Approximate area of circle.

SOLUTION:

Consider the figure attached.

let the radius of circle be x\text{ cm}

radius of circle =\frac{\text{length of base of square}}{2}

                     x=\frac{5}{2}\text{ cm}

                     x=2.5\text{ cm}

Area of circle =\pi(radius)^2

                      =3.14\times(2.5)^2

                      =19.625\text{ cm}^2

Hence the area of circle that perfectly fits inside the square is 19.625\text{ cm}^2

6 0
3 years ago
Read 2 more answers
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