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Anvisha [2.4K]
4 years ago
5

The owner of a local nightclub has recently surveyed a random sample of n = 250 customers of the club. She would now like to det

ermine whether or not the mean age of her customers is over 30. If so, she plans to alter the entertainment to appeal to an older crowd. It not, no entertainment changes will be made. The appropriate hypothesis to test is:
Mathematics
1 answer:
seraphim [82]4 years ago
8 0

Answer:

The required hypothesis to test is H_0: \mu\leq 30 and H_1: \mu>30.

Step-by-step explanation:

Consider the provided information.

It is given that the nightclub has recently surveyed a random sample of n = 250 customers of the club.

She would now like to determine whether or not the mean age of her customers is over 30.

Null hypotheses is represents as H_0. Thus the null hypotheses is shown as:

H_0: \mu\leq 30

The alternative hypotheses is represents as H_1. Thus the alternative hypotheses is shown as:

H_1: \mu>30

Hence, the required hypothesis to test is H_0: \mu\leq 30 and H_1: \mu>30.

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Out of 22 players in a team, 10 of them have an average height of 1.50m while another 10 have an average height of 1.48m. The re
Sonja [21]

Answer:

1.5 meters

Step-by-step explanation:

We know that the sum of all of the data in a set = average * number of data.

Therefore, the sum of the first 10 is 1.5 * 10 = 15 meters, the sum of the second 10 is 1.48 * 10 = 14.8 meters and the sum of the last 2 is 1.6 * 2 = 3.2 meters for a total of 15 + 14.8 + 3.2 = 33 meters. This means that the mean is 33 / 22 = 1.5 meters.

6 0
3 years ago
Read 2 more answers
Question five for geometry quiz
Helga [31]

The two tangents are parallel to each other because the two lines perpendicular to the same line are parallel to each other.

Lk + JK = JL




The answer is Parallel to each other
3 0
3 years ago
The wildlife department has been feeding a special food to rainbow trout fingerlings in a pond. based on a large number of obser
Liono4ka [1.6K]
The normal distribution curve for the problem is shown below

We need to standardise the value X=405.5 by using the formula

z-score= \frac{X-Mean}{Standard Deviation}
z-score= \frac{405.5-402.7}{8.8} =0.32

We now need to find the probability of z=0.32 by reading the z-table

Note that z-table would give the reading to the left of z-score, so if your aim is to work out the area to the right of a z-score, then you'd need to do:

P(Z\ \textgreater \ z)=1 - P(Z\ \textless \ z)

from  the z-table, the reading P(Z\ \textless \ 0.32) gives 0.6255

hence, 
P(Z\ \textgreater \ 0.32)=1-0.6255=0.3475

The probability that the mean weight for a sample of 40 trout exceeds 405.5 gram is 0.3475 = 34.75%

7 0
3 years ago
The cost of Nate's dinner including a 15% tip was $43.70. What was the cost of dinner alone?
Nookie1986 [14]

Answer:

The cost of dinner alone was $37.145

Step-by-step explanation:

15%=0.15----Convert your percentage into a decimal

43.70*0.15=6.555----Multiply the cost of dinner with the decimal

$43.70-$6.555=$37.145----Subtract the last number(6.555) from the total(43.70) to get the cost of dinner alone of $37.145 -This is making you subtract the percentage from the total!

I hope this helped!

7 0
3 years ago
Write an equation for the description.<br> Two-thirds a number x plus 4 is 6.
antiseptic1488 [7]
2/3x + 4=6. Is that what you mean?
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3 years ago
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