Anything withdrawn you subtract. Then, you know the total and you know what you had. Subtract total from what you had and you will see the change.
1735.97-100=1635.97
1668.71-1635.97=32.74
By Hand
Step 1:
Put the numbers in order.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 2:
Find the median.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 3:
Place parentheses around the numbers above and below the median.
Not necessary statistically, but it makes Q1 and Q3 easier to spot.
(1, 2, 5, 6, 7), 9, (12, 15, 18, 19, 27).
Step 4:
Find Q1 and Q3
Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data.
(1, 2, 5, 6, 7), 9, ( 12, 15, 18, 19, 27). Q1 = 5 and Q3 = 18.
Step 5:
Subtract Q1 from Q3 to find the interquartile range.
18 – 5 = 13.
Well, if it is increasing at a fixed rate of 2 mm/s, then the volume would still be increasing at a rate of 2 mm/s when the diameter is 80 mm, if I understand your question correctly.
The cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7
<em><u>Solution:</u></em>
Let "c" be the cost of 1 chocolate cake
Let "v" be the cost of 1 vanilla cake
<em><u>Jenny sold 14 chocolate cakes and 5 vanilla cakes for 119 dollars</u></em>
Therefore, we can frame a equation as:
14 x cost of 1 chocolate cake + 5 x cost of 1 vanilla cake = 119

14c + 5v = 119 ------- eqn 1
<em><u>Natalie sold 10 chocolate cakes and 10 vanilla cakes for 130 dollars</u></em>
Therefore, we can frame a equation as:
10 x cost of 1 chocolate cake + 10 x cost of 1 vanilla cake = 130

10c + 10v = 130 -------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
Multiply eqn 1 by 2
28c + 10v = 238 ------ eqn 3
<em><u>Subtract eqn 2 from eqn 3</u></em>
28c + 10v = 238
10c + 10v = 130
( - ) --------------------------
18c = 108
c = 6
<em><u>Substitute c = 6 in eqn 1</u></em>
14(6) + 5v = 119
84 + 5v = 119
5v = 119 - 84
5v = 35
v = 7
Thus cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7
Answer:
What is an equation of the line in point-slope form?
y + 1 = (1/3)(x + 2)
How can the point-slope form be written in function notation?
f(x) = (1/3)x - (1/3)
Step-by-step explanation: