15.
6 pachages
each pcage has 30
6*30=180 total
17 left over
how many used
used=total-left over
used=180-17
used=163
16. xy is 2 digit number
multiplules of 10 (whole multipules) always end with 0 so y=0
and has 3 as one of its factors
factors of 3 is 3,6,9,12
30,60,90 is answer
17.
30 in 9 parks
30 times 9
30=10 times 3
3*10*9
group the 3 and 9
10*(3*9)
3*9=27
10*(27)
270
15. 163
16. 30,60,90
17. see above, 270
Seeing as there are three coins, which means there are 3 heads and 3 tails.There's only a 50% chance it'll land on either side one one coin. I believe the chances to get two heads, and one tail would be somewhere around 80%, since there are only 8 possible outcomes.
Answer:
194
Step-by-step explanation:
Recall 2 rules to solve this easily:
1. 
2. 
<em>Now, if we let a = 7 and 
, we can say the problem is basically of the form:</em>
This can be simplified using the rules:
Now we can plug the values of a and b we initially thought of (remember though 
):
194 is the final answer.
Answer:
Dh
Step-by-step explanation:
BBC CNN bfhjhghjjhgh
Eight and five hundred seventeen thousandths
and
8 + .5 + .01 +.007
