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JulijaS [17]
3 years ago
13

Plz help me with this

Mathematics
1 answer:
Artemon [7]3 years ago
6 0

Answer:

C Is the corect answer

Step-by-step explanation:

Brcause you multiple the 4 and 8 = 38

plus 3,000 = 7483 and you dicide 7483/2

= 250r + 250

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What is 1/4 times 2/4
boyakko [2]
1/4= 0.25
2/4= 1/2 = 0.5
0.25 x 0.5 = 0.125
0.125 = 1/8
8 0
3 years ago
The 'Queen Mary' used to sail across the Atlantic Ocean The ships usual speed was 33 miles per hour. On average, the ship used f
makkiz [27]
13403.07692307692 i think is the answer because you multiply 5280 by 33 and then divide by 13.
6 0
3 years ago
calculate the height at 3 seconds given that the rocket travels 85 feet per second and starts on a launch pad 15 feet of the gro
Airida [17]

Answer:

The height of the rocket at 3 seconds is 270 feet

Step-by-step explanation:

To calculate the height of the rocket at 3 seconds,

First, we will determine the height the rocket has traveled in 3 seconds

The height traveled by the rocket is given by

Height (h) = Velocity (v) × Time (t)

From the question,

The rocket travels 85 feet per second, that is the velocity of the rocket is 85 feet per second,

Now,

v = 85 feet / second

t = 3 seconds

Hence,

Height (h) = 85 feet /second × 3 seconds

Height = 255 feet

∴ the rocket would have traveled 255 feet in 3 seconds,

But, the rocket starts on a launch pad 15 feet of the ground,

Then, the height of the rocket at 3 seconds is

255 feet + 15 feet = 270 feet.

Hence, the height of the rocket at 3 seconds is 270 feet

4 0
3 years ago
If y varies directly as x, find the constant of variation if y= 34 when x= 2
bearhunter [10]
The answer is C

y=kx. where k is a constant
sub y=34,x=2
2k=34
k=17
7 0
3 years ago
What is the simplified form of the following expression?
USPshnik [31]

Option C:

$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}

Solution:

Given expression is

$\sqrt[3]{\frac{4 x}{5}}

Note: \sqrt[3]{125}=\sqrt[3]{{5^3}}  = 5

To find the correct expression for the above simplified expression.

Option A: \frac{\sqrt[3]{4 x}}{5}

5 can be written as \sqrt[3]{125}.

$\frac{\sqrt[3]{4 x}}{5}=\frac{\sqrt[3]{4 x}}{\sqrt[3]{125} }

       $=\sqrt[3]{\frac{4x}{125} }

It is not the given simplified expression.

Option B: \frac{\sqrt[3]{20 x}}{5}

$\frac{\sqrt[3]{20 x}}{5}=\frac{\sqrt[3]{20 x}}{\sqrt[3]{125} }

         $=\sqrt[3]{\frac{20x}{125} }

Cancel the common factor in both numerator and denominator.

         $=\sqrt[3]{\frac{4x}{25} }

It is not the given simplified expression.

Option C: \frac{\sqrt[3]{100 x}}{5}

$\frac{\sqrt[3]{100 x}}{5}=\frac{\sqrt[3]{100 x}}{\sqrt[3]{125} }

           $=\sqrt[3]{\frac{100x}{125} }

Cancel the common factor in both numerator and denominator.

           $=\sqrt[3]{\frac{4 x}{5}}

It is the given simplified expression.

Option D: \frac{\sqrt[3]{100 x}}{125}

$\frac{\sqrt[3]{100 x}}{125}=\frac{\sqrt[3]{100 x}}{5^3}

It is not the given simplified expression.

Hence Option C is the correct answer.

$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}

3 0
3 years ago
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