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Harman [31]
2 years ago
7

Ill give brainlist

Mathematics
1 answer:
Mariana [72]2 years ago
7 0

The missing step 2 should be;

The quantity of the sum of thirty six plus two divided by 0.5 − 14.8 ÷ 8

The missing step 6 would be that; 76 - 1.85

<h3>How to Solve Mathematical Order of Operations?</h3>

We want to know the steps to solving the expression the quantity of the sum of six squared plus two divided by the absolute value of negative 0.5 − 14.8 ÷ 8

This can be expressed as;

6² + 2 ÷ |-0.5| - 14.8 ÷ 8

Thus, the next step which is step 2 should be;

The quantity of the sum of thirty six plus two divided by 0.5 − 14.8 ÷ 8

The missing step 6 would be that;

76 - 1.85

Read more about Order of Operations at; brainly.com/question/27529825

#SPJ1

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What number is 16% of 64, To The nearest tenth?
MatroZZZ [7]
16% of 64 is 10.24 so rounding that to the nearest tenth is 10.2.
3 0
3 years ago
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How do I solve this question?
olya-2409 [2.1K]

Hello,

we can simplify as below

\dfrac{(2p^3q^4)^4}{(-3q^5)^2}*\dfrac{9}{(4p^2q)^2}=\dfrac{2^4p^{12}q^{16}3^2}{3^2q^{10}4^2p^4q^2}=p^{12-4}q^{16-10-2}=p^{8}q^{4}=p^{a+b}q^{b-a}

So it means that

8 = a+b

4 = b-a

8+4 = a+b+b-a=2b

2b = 12

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and a = 6 - 4 = 2

hope this helps

7 0
3 years ago
Stephanie had a total of 80 pieces of $ 2 and $ 10 notes. After spending 2/5 of her $ 2 notes and 8 pieces of her $ 10 notes, sh
Ghella [55]

Answer:

$440

Step-by-step explanation:

notes $2 - n

notes $10 - m

n + m = 80 ----------> m = 80 - n

1 - 2/5 = 3/5

\frac{3}{5} * n = m - 8

\frac{3}{5} * n = 80 - n - 8 \\\\\frac{3}{5} * n + n = 72\\\\\frac{8}{5} * n = 72\\n = 45 \\m = 35\\

45 * $2 + 35 * $10 = 90 + 350 = $440

3 0
3 years ago
3/10=n/50? I really need help
xeze [42]
The answer is n=15 because you have to simplify
8 0
3 years ago
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Slice each system of linear equations by multiplying <br> 3x+3y=12 <br> 6x+11y=14
GalinKa [24]

Answer:

  (x, y) = (6, -2)

Step-by-step explanation:

Sometimes this solution method is called "addition" or "elimination." You want to multiply one or both equations by a value or values that make the coefficients of one of the variables be opposites. Then when you add the equations, the result is an equation without that variable. (One variable has been eliminated.)

Multiply the first equation by -2 to make its x-coefficient the opposite of that in the second equation. Then add the two equations:

  -2(3x +3y) = -2(12)

  -6x -6y = -24

Add the second equation ...

  (-6x -6y) +(6x +11y) = (-24) +(14)

  5y = -10 . . . . . simplify

  y = -2 . . . . . . . divide by 5

__

  3x +3(-2) = 12 . . . . . substitute into the first equation

  3x = 18 . . . . . . . . . . add 6

  x = 6 . . . . . . . . . . . . divide by 3

The solution is (x, y) = (6, -2).

6 0
3 years ago
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