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Paul [167]
3 years ago
15

Which phase change represents a decrease in entropy?(1) solid to liquid (3) liquid to gas(2) gas to liquid (4) solid to gas

Chemistry
1 answer:
emmainna [20.7K]3 years ago
7 0

Answer : The correct option is, (2) gas to liquid

Explanation :

Entropy : It is defined as the measurement of randomness or disorderedness in a system.

The order of entropy will be,

As we are moving from solid state to liquid state to gaseous state, the entropy will be increases due to the increase in the disorderedness.

As we are moving from gaseous state to liquid state to solid state, the entropy will be decreases due to the decrease in the disorderedness.

In option 1, 3 and 4, the entropy increases. while in option 2, the entropy decreases.

Hence, the correct option is, (2) gas to liquid

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Answer:

I kinda forgot. I'm sorry if I didn't answer your question.

Explanation:

7 0
3 years ago
What is the percent composition by mass of chlorine in LiCI
Lelechka [254]

Answer: Lithium (Li) 16.373%

Chlorine (Cl) 83.627%

Explanation:

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Which of the following is an oxidation-reduction reaction? a. HCl(aq) + LiOH(aq) → LiCl(aq) + H2O(l) b. Pb(C2H3O2)2(aq) + 2 NaCl
saw5 [17]

Answer: Option (d) is the correct answer.

Explanation:

A reaction in which there occurs change in oxidation state of reacting species is known as an oxidation-reduction reaction.

(a)    HCl(aq) + LiOH(aq) \rightarrow LiCl(aq) + H_{2}O(l)

Will be written as:

H^{+} + Cl^{-} + Li^{+} + OH^{-} \rightarrow Li^{+} + Cl^{-} + H^{+} + OH^{-}

In this reaction, there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.

(b)   Pb(C_{2}H_{3}O_{2})_{2}(aq) + 2NaCl(aq) \rightarrow PbCl_{2}(s) + 2 NaC_{2}H_{3}O_{2}(aq)

Will be written as:

  Pb^{2+} + 2C_{2}H_{3}OO^{-} + 2Na^{+} + 2Cl^{-} \rightarrow Pb^{2+} + 2Cl^{-} + 2Na^{+} + 2C2H3OO^{-}

Similarly here,  there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.

(c)   NaI(aq) + AgNO_{3}(aq) \rightarrow AgI(s) + NaNO_{3}(aq)

Will be written as:

Na^{+} + I^{-} + Ag^{2+} + NO^{2-}_{3} \rightarrow AgI(s) + Na^{+} + NO^{2-}_{3}(aq)

Here, also there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.

(d)    Mg(s) + 2 HCl(aq) \rightarrow MgCl_{2}(aq) + H_{2}(g)

So, here there occurs change in oxidation state of Mg from 0 to +2 and oxidation state of H changes from +1 to 0. Hence, it is an oxidation-reduction reaction.

Thus, we can conclude that Mg(s) + 2 HCl(aq) \rightarrow MgCl_{2}(aq) + H_{2}(g) is an oxidation-reduction reaction.

7 0
3 years ago
Pls help I will give u points pls
True [87]

Answer:

i think D

Explanation:

3 0
3 years ago
Which of the following changes depending on the strength of the gravity field it is in?
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