Answer:HNO₃ and NO³⁻ would not function as buffer
Explanation:
The buffer solution are usually prepared by using any weak acid (which would partially dissociate) and mixing this weak acid with its own conjugate base or any weak base (which would partially dissociate) and mixing with with its conjugate acid.
A buffer solution is a solution which resists change in pH of the solution.
Since nitric acid is a very strong acid and hence neither nitric acid HNO₃ or its conjugate base NO³⁻ anionb is suitable for the preparation of buffer solution.
HCO³⁻ is a weak acid and hence it can form a buffer solution with its conjugate base CO₃²-. so they can be used to form buffer.
C₂H₅COOH is a weak acid and hence it can also form buffer solution with its conjugate base.
So only HNO₃and NO³⁻ would not be able to form buffer
So option a is the answer.
According to the gas law, the pressure of the gas is related to the temperature when the volume is constant as P1/T1=P2/T2. So the pressure will increase and the container may explode.
Combination reaction. Two or more substances react to form a single substance.
Answer:
Explanation:
From the information given:
Feed F = 150.0 kmol/hr
The saturated liquid mixture of the distillation column is 
= 30%
Reflux ration = 2.0%
methanol distillate mole fraction 
= 0.990
recovery of methanol in the distillate = 97.0%
The distillate flow rate D can be determined by using the formula;
D = 0.97 × 150 × 0.3
D = 43.65 kmol/h
The bottom flow rate Balance B on the column is:
F = D + B
150 = 43.65 + B
B = ( 150 - 43.65 )kmol/h
B = 106.35 kmol/h
The methanol mole fraction in the bottom 
can be computed by using the formula:
150(0.3) = 43.65(0.999) + 106.3(
)
45 = 43.60635 + 106.3()
45 - 43.60635 = 106.3()
1.39365 = 106.3()
= 1.39365 / 106.3
= 0.013
the fractional recovery of water in the bottoms f is calculated as:
f = 0.99969
Here's your answer :)
C7H6O3 (Salicylic acid) + C4H6O3 (Ethanoic anhydride) => C9H8O4 (Aspirin) + C2H4O2 (Acetic acid)
3.54 g / 138.12 g·C7H6O3 mol−1 = 0.0256 moles C7H6O3.
From eqn, 1 mole C7H6O3 reacts with 1 mole C4H6O3 so 0.0256 moles C4H6O3 reacted.
Mass acetic anhydride needed = 0.0256 mol * 102.0886 g mol-1 = 2.61 g (to 3 sig fig).
