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marishachu [46]
2 years ago
10

Pls help I will give u points pls

Chemistry
1 answer:
True [87]2 years ago
3 0

Answer:

i think D

Explanation:

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Which of these elements is unlikely to form covalent bonds? s, h, mg, ar, si?
kari74 [83]
<span>Answer: K because it is metal and typically forms ionic bonds. Ar is also unlikely to form any bonds because it has a full outer shell of electrons, but it can form covalent bonds.</span>
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A sample of vinegar has a hydronium concentration of 1.6 × 10-3 M. What is the pH of the vinegar?
loris [4]
PH is defined as the negative log of Hydronium Ion concentration.

So, in order to find the pH of vinegar, we find the negative log of its hydronium ion concentration.

pH=-log[ H_{3}O^{+}] \\  \\ &#10;pH=-log(1.6  * 10^{-3})  \\  \\ &#10;pH=2.8

So, the pH of given vinegar solution will be 2.8.

Therefore, the answer to this question is option B
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What dose the saying Stars must die for others to be born mean
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-> there isnt an exact answer

Explanation:

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I reccomend searching google for an exact answer

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2 years ago
What is the molar concentration of 5% acetic acid?
larisa [96]

Answer:Vinegar Is 5% Acetic Acid And Its Molarity Is 0.833M.

Explanation:

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3 years ago
Hydrogen and iodine react to form hydrogen iodide, like this: H_2 (g) + I_2 (g) rightarrow 2 HI(g) Also, a chemist finds that at
telo118 [61]

This is an incomplete question, here is a complete question.

Hydrogen and iodine react to form hydrogen iodide, like this:

H_2(g)+I_2(g)\rightarrow 2HI(g)

Also, a chemist finds that at a certain temperature the equilibrium mixture of hydrogen, iodine, and hydrogen iodide has the following composition:

Compound            Pressure at equilibrium

H_2                                   61.8 atm

I_2                                    46.5 atm

HI                                  52.3 atm

Calculate the value of the equilibrium constant K_p for this reaction. Round your answer to 2 significant digits.

Answer : The value of equilibrium constant K_p for this reaction is, 0.952

Explanation :

The given chemical reaction :

H_2(g)+I_2(g)\rightarrow 2HI(g)

The expression of K_p for above reaction follows:

K_p=\frac{(P_{HI})^2}{P_{H_2}\times P_{I_2}}

We are given:

P_{H_2}=61.8atm

P_{I_2}=46.5atm

P_{HI}=52.3atm

Putting values in above equation, we get:

K_p=\frac{(52.3)^2}{61.8\times 46.5}\\\\K_p=0.952

Therefore, the value of equilibrium constant K_p for this reaction is, 0.952

7 0
3 years ago
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