Answer:
Step-by-step explanation:
As you can see, this is a quadratic equation and if you were to graph this you would see that it is a parabola that opens down because of the negative leading coefficient (-34). The maximum profit would be at the vertex, of the graph. Therefore, we need to find the value of "y" when "x" is the line of symmetry. We find this by x=-b/(2a) where a = -34 and b = 1542:
x=-1542/(2)(-34)
x=-152/-68
x=152/68
We put this value of "x" into the original formula to find out the value of "y":
y=-34x^2+1542x-10037
y=(-34)(1542/68)^2+1542(1542/68)-10037
y= -17483.5588235 + 34967.1176471 -10037
y=7446.5588236
Therefore, the maximum profit would be $7446.56.
Hope this helps!
PLS MARK BRAINLIEST THIS TOOK A LOT OF TIME
Answer:
A numerical coefficient is a constant multiplier of the variables in a term. so it would be 3x cause it has a number and a variable.
a variable is a symbol which functions as a placeholder for varying expression or quantities, so x is the variable.
a constant term is a term in an algebraic expression that has a value that is constant or cannot change, because it does not contain any modifiable variables. so it would be the 2
Step-by-step explanation:
Answer:
if donuts are 2 for each and cookies for 1 each it could be
X x 2 and X x 1
one equation could be 4 donuts for 2$ and 7 cookies for 1$
The probability that a 2 or 3 is rolled at least once is 0.14.
<h3>
Probability of not rolling a 2 or 3 in a single die roll of two dice</h3>
when a six die is rolled once there is 11/12 probability of not rolling 2 or 3.
rolling a six sided die two times, p(2 or 3)' = 11/12
rolling a six sided die four times, p(2 or 3)' = (11/12)² = 121/144
the probability that a 2 or 3 is rolled at least once is calculated as follows;
P = 1 - p(2 or 3)'
P = 1 - 121/144
P = 20/144
P = 0.14
Thus, the probability that a 2 or 3 is rolled at least once is 0.14.
Learn more about probability here: brainly.com/question/24756209
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Answer:
28 non-blue marbles.
Step-by-step explanation:
Initial probability of choosing a blue marble = 4/12
Let the number of non-blue marbles to be added be x.
(cross multiply)
