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mylen [45]
3 years ago
9

After extensive measurements of the time necessary to complete the first homework assignment, a teacher determines that there is

a population mean of 100 and a stardard deviation of 20. If she samples a class of 60 students and calculates a mean of 96 minutes, what is the z statistic (round to the nearest 2 decimal places, don't forget a negative sign if necessary)?
Mathematics
1 answer:
MaRussiya [10]3 years ago
4 0

Answer: -1.55

Step-by-step explanation:

Given : Mean : \mu=100

Standard deviation : \sigma=20

Sample size : n=60

Sample mean : \overline{x}=96

The test statistic for the population mean is given by :-

z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

\Rightarrow\ z=\dfrac{96-100}{\dfrac{20}{\sqrt{60}}}=-1.54919333848\approx-1.55

Hence, the value of z statistic = -1.55

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