In order to solve this question we first have to break down the terms.
Sum = Adding
Times = Multiplying.
The question states "3 times the sum of a number n and 12 is 45". In written form, it would be the following:
3(12+n) = 45
To solve this you first divide both sides by three and you'd be left with the following:
(12+n) = 15.
Then subtract 12 from both sides. Leaving you with:
n = 3
Any arithmetic sequence can be expressed as:
a(n)=a+d(n-1), a=initial value, d=common difference, n=term number.
The common difference is the constant difference found by subtracting the previous term from any term. In this case:
d=2-1 3/5=1 3/5-1 1/5=-2/5=-0.4 and we can easily see that the first term is 2 so
a(n)=2-0.4(n-1) which can be simplified...
a(n)=2-0.4n+0.4
a(n)=2.4-0.4n, so the 25th term is:
a(25)=2.4-0.4(25)
a(25)= -7.6 or if you prefer...
a(25)= -7 3/5
Step-by-step explanation:
1. Choose arbitrary points A and B in the plane and draw segment AB.
2. Raise a perpendicular m to AB at A.
3. Raise a perpendicular n to AB at B.
4. Choose an arbitrary point C on line n.
5. Drop a perpendicular from point C to line m. Let D be the foot of this perpendicular.
6. Then quadrilateral ABCD is a rectangle.
Step 1
find the coordinates of the factory
the <span>factory is 104 miles due north of the warehouse
the coordinates of the warehouse are (39,-52)
coordinates of the factory------> (39,-52+104)------> (39,52)
step 2
find the distance warehouse to airport
let
A coordinates of warehouse-------> A( 39,-52)
B coordinates of airport---------> B(-39,52)
C coordinates of factory-------> C(39,52)
distance AB=</span>√[(52+52)²+(-39-39)²]------> distance AB=130 miles
<span>
step 3
find the distance airport to factory
B(-39,52)
</span>C(39,52)
distance BC=√[(52-52)²+(39+39)²]-----> distance BC=39 miles
<span>the total number of miles=distance AB+distance BC---> 130+39
</span><span>the total number of miles=169 miles
</span>
the answer is
169 miles
Answer:
52630
Step-by-step explanation:
Simplify into numbers.
30 + 2000 + 40000 + 600 + 10000
Add.
52630
