Answer:
See below
Step-by-step explanation:
First, lets see how many feet of the original Eiffel tower (O) are represented in 1 foot of Caesar's tower model (M). We know that 1.5 foot is equal to 984 feet of the original, so we can say:
1.5 M = 984 O, this is our equivalence.
Now divide both sides by 1.5
1.5 M / 1.5 = 984 O / 1.5
1 M = 656 O
So, 1 foot of Cesar's Model is 684 feet of the original tower. We also know that 1 foot is equal to 12 inches, so we can say that 12 inches of Cesar Model (12 m) are equivalent to 656 feet of the original tower. So:
12 m = 656 O
If we divide both sides by 12:
m = 656/12 O
m = 56.67
So, 1 inch in Cesar's model represent 56.67 feet of the original Eiffel Tower.
Lets verify our result by multiplying 56.67 by 12 to get 1 feet and then by 1.5 to get the measure of the model:
56.67*12*1.5 = 984 feet, which is the height of the Eiffel tower.
Scale: 1 inch = 56.67 feet
