(-6,-4)
the point D can shift left 2 units which would be at that point
Answer:
13, 14, 15
Step-by-step explanation:
Let x = age of one of the siblings
Since the age of the siblings are consecutive integers, the age of the next sibling would be x + 1 and the age of the third sibling would be x + 2
x +( x +1) + (x +2) = 42
3x + 3 = 42
collect like terms and solve for x
x = 13
The age of the first sibling is 13
The age of the second sibling is x + 1 = 13 + 1 = 14
The age of the third sibling is x + 2 = 13 + 2 = 15
Answer:
D) 0 = 2(x + 5)(x + 3)
Step-by-step explanation:
Which of the following quadratic equations has no solution?
We have to solve the Quadratic equation for all the options in other to get a positive value as a solution for x.
A) 0 = −2(x − 5)2 + 3
0 = -2(x - 5) × 5
0 = (-2x + 10) × 5
0 = -10x + 50
10x = 50
x = 50/10
x = 5
Option A has a solution of 5
B) 0 = −2(x − 5)(x + 3)
Take each of the factors and equate them to zero
-2 = 0
= 0
x - 5 = 0
x = 5
x + 3 = 0
x = -3
Option B has a solution by one of its factors as a positive value of 5
C) 0 = 2(x − 5)2 + 3
0 = 2(x - 5) × 5
0 = (2x -10) × 5
0 = 10x -50
-10x = -50
x = -50/-10
x = 5
Option C has a solution of 5
D) 0 = 2(x + 5)(x + 3)
Take each of the factors and equate to zero
0 = 2
= 0
x + 5 = 0
x = -5
x + 3 = 0
x = -3
For option D, all the values of x are 0, or negative values of -5 and -3.
Therefore the Quadratic Equation for option D has no solution.
Answer:
a) AB = 17 m
b) AC = 20.8 m
Step-by-step explanation:
Pythagorean theorem
a^2 + b^2 = c^2
a)
AB^2 = (26-11)^2 + 8^2
AB^2 = 15^2 + 8^2
AB^2 = 225 + 64
AB^2 = 289
AB = 17 m
b)
AC^2 = AB^2 + BC^2
AC^2 = 17^2 + 12^2
AC^2 =289 + 144
AC^2 = 433
AC = 20.8 m
