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maw [93]
3 years ago
11

Simplify the expression below 12 divided by (2+1)

Mathematics
1 answer:
maksim [4K]3 years ago
7 0

Answer:

12 divide by 2+1

2+1=3 so

12/3

4

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Sandy is getting ready for the day. She can wear either a balck or white shirt and then either pants, shorts, or a skirt. Create
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Black shirt and pants
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6 COMBINATIONS TOTAL
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The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).21,42,84,...Find the 7th term.
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21,42,84,168,336,672, 1,344

Step-by-step explanation:

The pattern is to multiply the previous term by 2 to find the next term. The seventh term should be 1,344.

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23 points please help simplify the square root sqrt (32x^2) if x>=0
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4√2x.

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What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove
wolverine [178]

Answer:

The solutions are:

b=0,\:b=4

Step-by-step explanation:

Considering the expression

  • \frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

Solving the expression

\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c

5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2

5b^3-10=6b^3-4b^2-10

\mathrm{Switch\:sides}

6b^3-4b^2-10=5b^3-10

6b^3-4b^2-10+10=5b^3-10+10

6b^3-4b^2=5b^3

\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}

6b^3-4b^2-5b^3=5b^3-5b^3

b^3-4b^2=0

Using\:the\:Zero\:Factor\:Principle: if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

So,

b=0,b-4=0

b=0,b=4

Therefore, the solutions are:

b=0,\:b=4

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3 years ago
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