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Gemiola [76]
3 years ago
6

2. Describe the process used to solve an equation with variables on both sides.

Mathematics
1 answer:
Marat540 [252]3 years ago
6 0

Answer:

After simplifying, the first step in solving an equation with a variable on both sides is to Get The Variable On One Side. This is done by reversing the addition or subtraction of one of the terms with the variable. In other words, we must add to both sides or subtract from both sides one of the quantities that contains the variable. It is generally easier to add or to subtract the smaller quantity from the larger quantity, so we are working with positive coefficients, but either way works

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HELPPPPPPPPP<br><br> Write the quadratic expression to represent the pattern to the right
Lerok [7]

Answer:

  • n^2 + 2n - 1

Step-by-step explanation:

<u>Figure 1</u>

  • 2*2 - 2

<u>Figure 2</u>

  • 3*3 - 2

<u>Figure 3</u>

  • 4*4 - 2

<u>Equation for nth term</u>

  • (n + 1)^2 - 2 =
  • n^2 + 2n + 1 - 2 =
  • n^2 + 2n - 1
4 0
2 years ago
PLS HELP ASAP <br><br><br> TRUE<br> FALSE
WITCHER [35]
I think the correct answer would most likely be true
8 0
3 years ago
What is bigger 3.345 or 3.35 or 3.3
Sidana [21]
3.35 is bigger then 3.345
8 0
2 years ago
The length of a rectangular flower bed is 2ft longer than the width. If the area is 6ft, then what are the exact length and widt
Marizza181 [45]

Answer:

Exact dimensions:

width=-1+\sqrt{7}

length=-1+\sqrt{7}+2

length=1+\sqrt{7}

Approximate dimensions:

width=1.64575ft

length=1.64575+2

length=3.64575ft

Step-by-step explanation:

Let's assume width of rectangle is w ft

The length of a rectangular flower bed is 2ft longer than the width

so,

length =w+2

L=w+2

now, we can find area

A=L\times W

now, we can plug it

A=(w+2)\times w

A=w^2+2w

we are given area =6

so, we can set it equal

and then we can solve for w

w^2+2w=6

w^2+2w-6=0

we can use quadratic formula

ax^2+bx+c=0

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

now, we can compare and find a,b and c

a=1 , b=2 , c=-6

w=\frac{-2\pm \sqrt{2^2-4\cdot \:1\left(-6\right)}}{2\cdot \:1}

w=-1+\sqrt{7},\:w=-1-\sqrt{7}

we know that dimension can never be negative

so, we will only consider positive value

Exact dimensions:

width=-1+\sqrt{7}

length=-1+\sqrt{7}+2

length=1+\sqrt{7}

Approximate dimensions:

width=1.64575ft

length=1.64575+2

length=3.64575ft

7 0
3 years ago
which order pair is a solution of the equation? y-4=7(x-6) A. only (5,4) B. only (6,5) C. both (5,4) and (6,5) D. neither​
Svet_ta [14]

Answer:

option D. Neither

Step-by-step explanation:

y-4=7(x-6)

using (5,4):

4-4=7(5-6)

0=7(-1)

0=-7

using (6,5):

5-4=7(6-6)

1=7(0)

1=0

so option D is the answer

6 0
3 years ago
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