Answer:
The area of parallelogram ABCD is equal to the area of parallelogram EFGH.
Step-by-step explanation:
Given
Parallelogram ABCD
Parallelogram EFGH
Required
Compare the areas of both parallelograms
The area of a parallelogram is:
So: To do this, we plot ABCD and EFGH on a grid, then we measure the base and the height of both.
See attachment 1 for ABCD
In (1), we have:
So, the area is:
See attachment 2 for EFGH
In (2), we have:
So, the area is:
<em>By comparison, they both have the same areas</em>
I am pretty sure you subtract but in case it would be
(23,43) - (17,14).
(6,19) should be the answer
Use the formula for an arithmetic sequence: 
= nth term
a = the first term in the sequence
n = term you are looking for
d = common difference between the terms
Answers
1. <em>I'm assuming you meant to type 0.2, 0.6, 1, 1.4...</em>
In that case, it is increasing by 0.4, so the next three would be:
0.2 + (4-1)(0.4) = 1.8...
=> 1.8, 2.2, 2.6.
2. Here it's reducing by 0.25, so start with:
4 + (5-1)(-0.25) = 3...
=> 3, 2.75, 2.5
Answer:
see explanation
Step-by-step explanation:
To find the y- intercept let x = 0 in the function
g(0) = 0 - 0 - 84 = - 84 ← y- intercept
To find the x- intercepts let y = 0, that is
x² - 5x - 84 = 0
To factor the quadratic
Consider the factors of the constant term (- 84) which sum to give the coefficient of the x- term
The factors are - 12 and + 7, since
- 12 × 7 = - 84 and - 12 + 7 = - 5, thus
(x - 12)(x + 7) = 0
Equate each factor to zero and solve for x
x - 12 = 0 ⇒ x = 12
x + 7 = 0 ⇒ x = - 7
x- intercepts are x = - 7 and x = 12
Answer:
6
Step 1: Solve Square Root
Vx+3=x-3
x+3=(x-3)^2 (squared both sides)
x+3=x^2-6x+9
x+3-(x^2-6x+9)=0
(-x+1)(x-6)=0 (factor left side of equation)
-x+1=0 or x-6=0
x=1 or x=6
When you plug it in to check
1 (Doesn't Work)
6 (Work)
Therefore, 6 is your solution.
