Ask question

Ask question

All categories

3 years ago

10

On a coordinate plane, parallelograms A B C D and E F G H are shown. Parallelogram A B C D has points (4, 2), (7, 2), (4, 6), (1

, 6). Parallelogram E F G H has points (negative 2, 2), (negative 5, 2), (negative 6, 6), and (negative 3, 6). How do the areas of the parallelograms compare? The area of parallelogram ABCD is 4 square units greater than the area of parallelogram EFGH. The area of parallelogram ABCD is 2 square units greater than the area of parallelogram EFGH. The area of parallelogram ABCD is equal to the area of parallelogram EFGH. The area of parallelogram ABCD is 2 square units less than the area of parallelogram EFGH.

2 answers:

Fittoniya [83]3 years ago

8 0

Answer:

The area of parallelogram ABCD is equal to the area of parallelogram EFGH.

Step-by-step explanation:

Given

Parallelogram ABCD

$A = (4,2)$

$B = (7,2)$

$C =(4,6)$

$D = (1,6)$

Parallelogram EFGH

$E =(-2,2)$

$F = (-5,2)$

$G = (-6,6)$

$H = (-3,6)$

Required

Compare the areas of both parallelograms

The area of a parallelogram is:

$Area =Base * Height$

So: To do this, we plot ABCD and EFGH on a grid, then we measure the base and the height of both.

See attachment 1 for ABCD

In (1), we have:

$Base = 3\ units$

$Height = 4\ units$

So, the area is:

$A_1 = 3 * 4$

$A_1 = 12$

See attachment 2 for EFGH

In (2), we have:

$Base = 3\ units$

$Height = 4\ units$

So, the area is:

$A_2 = 3 * 4$

$A_2 = 12$

<em>By comparison, they both have the same areas</em>

LekaFEV [45]3 years ago

8 0

Answer:

C)

Step-by-step explanation:

e2020

You might be interested in

PLEASE HELP ASAP -- WITH THE WORKK<br><br>50 points

MAXImum [283]

Part-A:-

<h3>(f×g)=</h3>

$\\ \sf\longmapsto x^2+3x-70(4x-12)$

$\\ \sf\longmapsto 4x^2+12x-280-12x^2+36x+840$

$\\ \sf\longmapsto -8x^2+48x+560$

Now

$\\ \sf\longmapsto (f.g)(3)$

$\\ \sf\longmapsto -8(3)^2+48(3)+560$

$\\ \sf\longmapsto -72+144+560$

$\\ \sf\longmapsto 72+560$

$\\ \sf\longmapsto 632$

Part-B:-

$\\ \sf\longmapsto f(3)$

$\\ \sf\longmapsto (3)^2+3(3)-70$

$\\ \sf\longmapsto 9+9-70$

$\\ \sf\longmapsto 18-70$

$\\ \sf\longmapsto -52$

Now

$\\ \sf\longmapsto g(f(3))$

$\\ \sf\longmapsto g(-52)$

$\\ \sf\longmapsto 4(-52-3)$

$\\ \sf\longmapsto 4(-55)$

$\\ \sf\longmapsto -220$

Part:-C

$\\ \sf\longmapsto g(-2)$

$\\ \sf\longmapsto 4(-2-3)$

$\\ \sf\longmapsto 4(-5)$

$\\ \sf\longmapsto -20$

Now

$\\ \sf\longmapsto f(g(-2))$

$\\ \sf\longmapsto f(-20)$

$\\ \sf\longmapsto (-20)^2+3(-20)-70$

$\\ \sf\longmapsto 400-60-70$

$\\ \sf\longmapsto 400-130$

$\\ \sf\longmapsto 270$

Part-D:-

g×f=f×g

$\\ \sf\longmapsto (g.f)(-2)$

$\\ \sf\longmapsto -8(-2)^2+48(-2)+560$

$\\ \sf\longmapsto 32-96+560$

$\\ \sf\longmapsto -64+560$

$\\ \sf\longmapsto 496$

6 0

2 years ago

Function f is differentiable and decreasing for all real numbers. If y=f(2x^3 - 3x^2), for which of the following intervals of x

vichka [17]

Answer:

The terai region extends from the chure range in the north to the border of India in the south.lt covers 17 percent of total land of Nepal .this terai region is mostly flat and plain with alluvial fertile deposited by the rivers . the climate of the reason is hot and wet in summer and cold and dry in winter.Terai also called the granary of Nepal as more than half percent of people of Nepal depend on the vegetation of Terai region. Terai is plain, where more cultivation is possible. Cultivation is impossible in mountain region due to difficult topography and temperate region and even in hilly region with lots of vegetation it's not possible due to slope area. Terai is only the possible region where much cultivation is possible. Different kinds of vegetation, valuable medicinal herbs, important trees, etc. are found in Terai region. So, Terai region is called the granary of Nepal.The terai region extends from the chure range in the north to the border of India in the south.lt covers 17 percent of total land of Nepal .this terai region is mostly flat and plain with alluvial fertile deposited by the rivers . the climate of the reason is hot and wet in summer and cold and dry in winter.Terai also called the granary of Nepal as more than half percent of people of Nepal depend on the vegetation of Terai region. Terai is plain, where more cultivation is possible. Cultivation is impossible in mountain region due to difficult topography and temperate region and even in hilly region with lots of vegetation it's not possible due to slope area. Terai is only the possible region where much cultivation is possible. Different kinds of vegetation, valuable medicinal herbs, important trees, etc. are found in Terai region. So, Terai region is called the granary of Nepal.The terai region extends from the chure range in the north to the border of India in the south.lt covers 17 percent of total land of Nepal .this terai region is mostly flat and plain with alluvial fertile deposited by the rivers . the climate of the reason is hot and wet in summer and cold and dry in winter.Terai also called the granary of Nepal as more than half percent of people of Nepal depend on the vegetation of Terai region. Terai is plain, where more cultivation is possible. Cultivation is impossible in mountain region due to difficult topography and temperate region and even in hilly region with lots of vegetation it's not possible due to slope area. Terai is only the possible region where much cultivation is possible. Different kinds of vegetation, valuable medicinal herbs, important trees, etc. are found in Terai region. So, Terai region is called the granary of Nepal.

4 0

2 years ago

Help me please. Help

Nesterboy [21]

The answer is D!!!!!

4 0

3 years ago

AC=23,<br> AB=2x+2, and <br> BC=3x+6<br> Find BC.

Kryger [21]

Answer: 9

Step-by-step explanation:

8 0

3 years ago

Use the drop-down menus to label the graph according to its type. On a coordinate plane, a graph has two straight lines that con

romanna [79]

Relaction (but not a function)

6 0

3 years ago

Read 2 more answers