Question

On a coordinate plane, parallelograms A B C D and E F G H are shown. Parallelogram A B C D has points (4, 2), (7, 2), (4, 6), (1, 6). Parallelogram E F G H has points (negative 2, 2), (negative 5, 2), (negative 6, 6), and (negative 3, 6). How do the areas of the parallelograms compare? The area of parallelogram ABCD is 4 square units greater than the area of parallelogram EFGH. The area of parallelogram ABCD is 2 square units greater than the area of parallelogram EFGH. The area of parallelogram ABCD is equal to the area of parallelogram EFGH. The area of parallelogram ABCD is 2 square units less than the area of parallelogram EFGH.

Answer 1

Answer:

The area of parallelogram ABCD is equal to the area of parallelogram EFGH.

Step-by-step explanation:

Given

Parallelogram ABCD

$A = (4,2)$

$B = (7,2)$

$C =(4,6)$

$D = (1,6)$

Parallelogram EFGH

$E =(-2,2)$

$F = (-5,2)$

$G = (-6,6)$

$H = (-3,6)$

Required

Compare the areas of both parallelograms

The area of a parallelogram is:

$Area =Base * Height$

So: To do this, we plot ABCD and EFGH on a grid, then we measure the base and the height of both.

See attachment 1 for ABCD

In (1), we have:

$Base = 3\ units$

$Height = 4\ units$

So, the area is:

$A_1 = 3 * 4$

$A_1 = 12$

See attachment 2 for EFGH

In (2), we have:

$Base = 3\ units$

$Height = 4\ units$

So, the area is:

$A_2 = 3 * 4$

$A_2 = 12$

By comparison, they both have the same areas

Answer 2

Answer:

C)

Step-by-step explanation:

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