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irakobra [83]
3 years ago
13

The public library has to move 42,000 books to its new location. The movers can pack an average of 45 books in every box. The tr

uck that the movers are using holds 250 boxes. How many boxes will the library need? How many trips will the movers need to make with the truck?
Mathematics
1 answer:
Anni [7]3 years ago
7 0

Answer:

<h2> 934boxes</h2><h2> 4 trips</h2>

Step-by-step explanation:

Given the total number of books 42,000

Ok, firstly let us calculate the number of boxes required, given that a box can contain 45 books

number of boxes= 42,000/45  

number of boxes=933.3 boxes

approximately 934boxes

Also, given that the truck can carry online 250 boxes in one trip

then it must make 934/250= 3.7 trips

approximately the truck will make 4 trips to carry all the boxes

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Idk wat to do.....<br>........​
oksano4ka [1.4K]

Answer:

Mean : 95

Median : 85

Mode : 90

Part B : Impossible

Step-by-step explanation:

We can make an equation to find the mean using the first 5 history test scores.

85=\frac{80+75+90+75+95+n}{6} \\ \\ 85=\frac{415+n}{6} \\ \\ 510=415+n \\ \\ n=95

So a 95 would be needed to have a mean of 85.

Next, the median.

First, we sort the first 5 history scores from least to greatest.

We get 75, 75, 80, 90, 95.

Since, 80 is the middle value, it will be used in the calculation of the median.

We can make an equation with this.

82.5=\frac{80+n}{2} \\ \\ 165=80+n \\ \\ n=85

So a score a 85 would be needed to have a median of 82.5

Thirdly, the mode.

Since 90 is already in the set once, we can just have Maliah score another 90 to make 90 the mode (with the exception of 75 of course).

Finally, Part B.

We can use the equation we had for the first mean calculation but change 85 to 90.

90=\frac{80+75+90+75+95+n}{6} \\ \\ 90=\frac{415+n}{6} \\ \\ 540=415+n \\ \\ n=125

So Maliah would need a score of 125 to make her mean score 90, but since the range is only from 0-100, it is impossible.

8 0
3 years ago
Based on past experience, a telemarketing firm has found that calls to prospective customers take an average of 2.0 minutes, wit
xenn [34]

Answer: Our required probability would be 0.9641.

Step-by-step explanation:

Since we have given that

Number of hours he works a day = 8

So, Number of minutes he worked in a day = 8\times 60=480\ minutes

Number of calls = 220

So, Average =\bar{x}=\dfrac{480}{220}=2.18\ minutes

Standard deviation =s=\dfrac{\sigma}{\sqrt{n}}=\dfrac{1.5}{\sqrt{220}}=0.10

Mean = μ = 2.0 minutes

Standard deviation = σ = 1.5 minutes

Using the normal distribution, we get that

z=\dfrac{\bar{x}-\mu}{s}\\\\z=\dfrac{2.18-2.0}{0.10}\\\\z=1.8

So, the probability that Albert will meet or exceed his quota would be

P(X\leq 2.18)=P(z\leq 1.8)=0.9641

Hence, our required probability would be 0.9641.

6 0
3 years ago
Question Bellow
Tcecarenko [31]

Answer:

A, B, C

Step-by-step explanation:

Look at how many field goals were actually made and order them from least to greatest- 12, 15, 19. They are already listed from least to greatest in the table.

6 0
3 years ago
Read 2 more answers
15% of the toddlers in a preschool class drink water with their lunch. How many toddlers are in the class if 3 drink water with
Naddika [18.5K]
15%=3
5%=1
5(20)=100
1(20)=20

So, there are 20 students in the class.
8 0
2 years ago
Read 2 more answers
three different are rung at intervals of 36 minutes 40 minutes and 48 minutes if they were rung together at 9 a.m. at what time
Lena [83]

To find the time in which all the bells ring together, we need to find the LCM of 36,40,48.

Prime factorization of 36=2×2×3×3

Prime factorization of 40=2×2×2×5

Prime factorization of 48=2×2×2×2×3

Hence, LCM of 36,40,48=2×2×2×2×3×3×5=720 seconds.

 

720seconds=  

60

720

​

minutes=12minutes

Hence, all the bells will ring together after 12 mi

6 0
2 years ago
Read 2 more answers
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